Tabular and Bar Graph Data Interpretation
Data Interpretation for IBPS PO Mains 2018. Tabular and Bar Graph Data Interpretation Questions. Tabular and Graph DI For IBPS PO/Clerk Prelims 2018. Welcome to the www.letsstudytogether.co online Quantitative Aptitude section. If you are preparing for upcoming IBPS PO/Clerk Prelims 2018, you will come across a section on Data Interpretation Section. Here we are providing you with “Tabular and Bar Graph Data Interpretation For IBPS PO/Clerk Prelims based on the latest pattern of your daily practice.
This “Tabular and Bar Graph Data Interpretation For IBPS PO/Clerk 2018 ” is also important for other banking exams such as IBPS PO, IBPS Clerk, SBI Clerk, IBPS RRB Officer, IBPS RRB Office Assistant, IBPS SO, SBI SO and other competitive exams.
Tabular and Bar Graph Data Interpretation Quiz  Set – 95
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Question 1 of 10
1. Question
Directions:(15) Answer the questions based on the information given below.
The bar graph below provides the information about the number of hours taken by pipes P, Q, R, S and T to empty pool M and pool N while working individually.
Pipes Q, R and S are opened alternately for an hour with pipe Q starting first and then pipe R and then pipe S. If they continue being opened in this pattern, then in how many hours would pool N be completely empty?
Correct
B. 2187/40 hours
Portion of pool N emptied in 1st 3 hours = 1/45 + 1/50 + 1/80 = (80 + 72 + 45)/3600 = 197/3600
So, portion of pool N emptied in 1st 54 hours = 18 × (197/3600) = 3546/3600
Portion of pool N remaining to be emptied = 1 – (3546/3600) = 54/3600 = 3/200
Time taken by Pipe Q alone to empty the remaining portion of pool N = (3/200)/(1/45) = 27/40 hours
So, total number of hours taken to empty pool N = 54 + (27/40) = 2187/40 hours
Incorrect
B. 2187/40 hours
Portion of pool N emptied in 1st 3 hours = 1/45 + 1/50 + 1/80 = (80 + 72 + 45)/3600 = 197/3600
So, portion of pool N emptied in 1st 54 hours = 18 × (197/3600) = 3546/3600
Portion of pool N remaining to be emptied = 1 – (3546/3600) = 54/3600 = 3/200
Time taken by Pipe Q alone to empty the remaining portion of pool N = (3/200)/(1/45) = 27/40 hours
So, total number of hours taken to empty pool N = 54 + (27/40) = 2187/40 hours

Question 2 of 10
2. Question
The bar graph below provides the information about the number of hours taken by pipes P, Q, R, S and T to empty pool M and pool N while working individually.
If pipes P and Q, both work at half of their original efficiencies and pipe R works at twice its original efficiency, then in how many hours would pool M be completely emptied on opening pipes P, Q and R together?
Correct
A. 1200/119 hours
Portion of pool M emptied by pipe P in one hour = 0.5 × (1/40) = 1/80
Portion of pool M emptied by pipe Q in one hour = 0.5 × (1/25) = 1/50
Portion of pool M emptied by pipe R in one hour = 2 × (1/30) = 1/15
Required time taken to empty pool M = 1/ (1/80 + 1/50 + 1/15) = 1/ ((15 + 24 + 80)/1200)
= 1200/119 hours
Incorrect
A. 1200/119 hours
Portion of pool M emptied by pipe P in one hour = 0.5 × (1/40) = 1/80
Portion of pool M emptied by pipe Q in one hour = 0.5 × (1/25) = 1/50
Portion of pool M emptied by pipe R in one hour = 2 × (1/30) = 1/15
Required time taken to empty pool M = 1/ (1/80 + 1/50 + 1/15) = 1/ ((15 + 24 + 80)/1200)
= 1200/119 hours

Question 3 of 10
3. Question
The bar graph below provides the information about the number of hours taken by pipes P, Q, R, S and T to empty pool M and pool N while working individually.
What is the difference between the time taken by pipe R and T together to empty pool M and the time taken by pipe R and T together to empty pool N?
Correct
B. 265/18 hours
Portion of pool M emptied by pipe R and T together in one hour = 1/30 + 1/10 = 4/30 = 2/15
So, time taken by pipe R and T together to empty the pool M = 1/ (2/15) = 15/2 hours
Portion of pool N emptied by pipe R and T together in one hour = 1/50 + 1/40 = 9/200
So, time taken by pipe R and T together to empty the pool N = 1/ (9/200) = 200/9 hours
Required difference = 200/9 – 15/2 = 265/18 hours
Incorrect
B. 265/18 hours
Portion of pool M emptied by pipe R and T together in one hour = 1/30 + 1/10 = 4/30 = 2/15
So, time taken by pipe R and T together to empty the pool M = 1/ (2/15) = 15/2 hours
Portion of pool N emptied by pipe R and T together in one hour = 1/50 + 1/40 = 9/200
So, time taken by pipe R and T together to empty the pool N = 1/ (9/200) = 200/9 hours
Required difference = 200/9 – 15/2 = 265/18 hours

Question 4 of 10
4. Question
The bar graph below provides the information about the number of hours taken by pipes P, Q, R, S and T to empty pool M and pool N while working individually.
Find the ratio of the number of hours taken by pipe S and T together to empty pool N to the number of hours taken by pipe Q and S together to empty pool M.
Correct
D. 32:15
Number of hours taken by pipe S and T together to empty pool N = 1/(1/80 + 1/40) = 1/(3/80) 80/3 hours
Number of hours taken by pipe Q and S together to empty pool M = 1/(1/25 + 1/25) = 1/(2/25) = 25/2 hours
Required ratio = 80/3: 25/2 = 32: 15
Incorrect
D. 32:15
Number of hours taken by pipe S and T together to empty pool N = 1/(1/80 + 1/40) = 1/(3/80) 80/3 hours
Number of hours taken by pipe Q and S together to empty pool M = 1/(1/25 + 1/25) = 1/(2/25) = 25/2 hours
Required ratio = 80/3: 25/2 = 32: 15

Question 5 of 10
5. Question
The bar graph below provides the information about the number of hours taken by pipes P, Q, R, S and T to empty pool M and pool N while working individually.
If pipes P, Q, R and S are working together to empty pool M and pipes Q, R, S and T are working together to empty pool N, then what is the difference between the fraction of pool M and the fraction of pool N emptied in 3 hours?
Correct
D. 211/1200
Portion of pool M emptied by pipes P, Q, R and S together in one hour = 1/40 + 1/25 + 1/30 + 1/25 = (15 + 24 + 20 + 24)/600 = 83/600
Portion of pool M emptied in 3 hours = 3 × (83/600) = 83/200
Portion of pool N emptied by pipes Q, R, S and T together in one hour = 1/45 + 1/50 + 1/80 + 1/40 = (80 + 72 +
45 + 90)/3600 = 287/3600
Portion of pool N emptied in 3 hours = 3 × (287/3600) = 287/1200
Required difference = 83/200 – 287/1200 = 211/1200
Incorrect
D. 211/1200
Portion of pool M emptied by pipes P, Q, R and S together in one hour = 1/40 + 1/25 + 1/30 + 1/25 = (15 + 24 + 20 + 24)/600 = 83/600
Portion of pool M emptied in 3 hours = 3 × (83/600) = 83/200
Portion of pool N emptied by pipes Q, R, S and T together in one hour = 1/45 + 1/50 + 1/80 + 1/40 = (80 + 72 +
45 + 90)/3600 = 287/3600
Portion of pool N emptied in 3 hours = 3 × (287/3600) = 287/1200
Required difference = 83/200 – 287/1200 = 211/1200

Question 6 of 10
6. Question
Directions: Answer the questions based on the information given below.
The table below provides the information about 5 different cylindrical tanks (P, Q, R, S and T) and each tank is full, filled with the mixture of oil and water. The table shows the radius and height of each tank and the percentage of oil in each tank with respect to the maximum volume of that tank.
Tank
Percentage of oil
Radius (in m)
Height (in m)
P
30%
3
14
Q
55%
7
10
R
20%
2
28
S
45%
4
14
T
60%
3
21
What is the ratio of the quantity of oil in tank Q to the quantity of oil in tank S?
Correct
D. 385:144
Volume of tank Q = (22/7) × 7^{2} × 10 = 1540 m^{3}
Volume of tank S = (22/7) × 4^{2} × 14 = 704 m^{3}
Quantity of oil in tank Q = 0.55 × 1540 = 847 m^{3}
Quantity of oil in tank S = 0.45 × 704 = 316.8 m^{3}
Required ratio = 847: 316.8 = 385: 144
Incorrect
D. 385:144
Volume of tank Q = (22/7) × 7^{2} × 10 = 1540 m^{3}
Volume of tank S = (22/7) × 4^{2} × 14 = 704 m^{3}
Quantity of oil in tank Q = 0.55 × 1540 = 847 m^{3}
Quantity of oil in tank S = 0.45 × 704 = 316.8 m^{3}
Required ratio = 847: 316.8 = 385: 144

Question 7 of 10
7. Question
The table below provides the information about 5 different cylindrical tanks (P, Q, R, S and T) and each tank is full, filled with the mixture of oil and water. The table shows the radius and height of each tank and the percentage of oil in each tank with respect to the maximum volume of that tank.
Tank
Percentage of oil
Radius (in m)
Height (in m)
P
30%
3
14
Q
55%
7
10
R
20%
2
28
S
45%
4
14
T
60%
3
21
The total capacity of tanks Q and T combined is approximately what percentage of the total capacity of the other 3 tanks combined?
Correct
A. 147%
Volume of tank P = (22/7) × 3^{2} × 14 = 396 m^{3}
Volume of tank Q = (22/7) × 7^{2} × 10 = 1540 m^{3}
Volume of tank R = (22/7) × 2^{2} × 28 = 352 m^{3}
Volume of tank S = (22/7) × 4^{2} × 14 = 704 m^{3}
Volume of tank T = (22/7) × 3^{2} × 21= 594 m^{3}
Required percentage = [(1540+ 594) / (396 + 352 + 704)] × 100 = 147%
Incorrect
A. 147%
Volume of tank P = (22/7) × 3^{2} × 14 = 396 m^{3}
Volume of tank Q = (22/7) × 7^{2} × 10 = 1540 m^{3}
Volume of tank R = (22/7) × 2^{2} × 28 = 352 m^{3}
Volume of tank S = (22/7) × 4^{2} × 14 = 704 m^{3}
Volume of tank T = (22/7) × 3^{2} × 21= 594 m^{3}
Required percentage = [(1540+ 594) / (396 + 352 + 704)] × 100 = 147%

Question 8 of 10
8. Question
The table below provides the information about 5 different cylindrical tanks (P, Q, R, S and T) and each tank is full, filled with the mixture of oil and water. The table shows the radius and height of each tank and the percentage of oil in each tank with respect to the maximum volume of that tank.
Tank
Percentage of oil
Radius (in m)
Height (in m)
P
30%
3
14
Q
55%
7
10
R
20%
2
28
S
45%
4
14
T
60%
3
21
If 15% of the mixture is taken out from each of the tanks R and T, then find the total amount of water taken out from both the tanks. [Note: 1m^{3} = 1000 litres]
Correct
A. 77880 litres
Volume of tank R = (22/7) × 2^{2} × 28 = 352 m^{3}
Volume of tank T = (22/7) × 3^{2} × 21 = 594 m^{3}
Required total quantity of water taken out = 0.15 × 0.8 × 352 + 0.15 × 0.4 × 594
= 42.24 + 35.64 = 77.88 m^{3}
= 77.88 × 1000 = 77880 litres
Incorrect
A. 77880 litres
Volume of tank R = (22/7) × 2^{2} × 28 = 352 m^{3}
Volume of tank T = (22/7) × 3^{2} × 21 = 594 m^{3}
Required total quantity of water taken out = 0.15 × 0.8 × 352 + 0.15 × 0.4 × 594
= 42.24 + 35.64 = 77.88 m^{3}
= 77.88 × 1000 = 77880 litres

Question 9 of 10
9. Question
The table below provides the information about 5 different cylindrical tanks (P, Q, R, S and T) and each tank is full, filled with the mixture of oil and water. The table shows the radius and height of each tank and the percentage of oil in each tank with respect to the maximum volume of that tank.
Tank
Percentage of oil
Radius (in m)
Height (in m)
P
30%
3
14
Q
55%
7
10
R
20%
2
28
S
45%
4
14
T
60%
3
21
The total quantity of water in tanks P and S combined is what percentage less than the total quantity of oil in tanks S and T combined?
Correct
C. 1.31%
Volume of tank P = (22/7) × 3^{2} × 14 = 396 m^{3}
Volume of tank S = (22/7) × 4^{2} × 14 = 704 m^{3}
Volume of tank T = (22/7) × 3^{2} × 21 = 594 m^{3}
Total quantity of water in tanks P and S combined = (1 – 0.3) × 396 + (1 – 0.45) × 704 = 664.4 m^{3}
Total quantity of oil in tanks S and T combined = 0.45 × 704 + 0.6 × 594 = 673.2 m^{3}
Required percentage = [(673.2 – 664.4) / 673.2] × 100 = 1.31%
Incorrect
C. 1.31%
Volume of tank P = (22/7) × 3^{2} × 14 = 396 m^{3}
Volume of tank S = (22/7) × 4^{2} × 14 = 704 m^{3}
Volume of tank T = (22/7) × 3^{2} × 21 = 594 m^{3}
Total quantity of water in tanks P and S combined = (1 – 0.3) × 396 + (1 – 0.45) × 704 = 664.4 m^{3}
Total quantity of oil in tanks S and T combined = 0.45 × 704 + 0.6 × 594 = 673.2 m^{3}
Required percentage = [(673.2 – 664.4) / 673.2] × 100 = 1.31%

Question 10 of 10
10. Question
The table below provides the information about 5 different cylindrical tanks (P, Q, R, S and T) and each tank is full, filled with the mixture of oil and water. The table shows the radius and height of each tank and the percentage of oil in each tank with respect to the maximum volume of that tank.
Tank
Percentage of oil
Radius (in m)
Height (in m)
P
30%
3
14
Q
55%
7
10
R
20%
2
28
S
45%
4
14
T
60%
3
21
What is the sum total of the curved surface area of tanks Q, R and T combined?
Correct
E. None of these
Curved surface area of tank Q = 2 × (22/7) × 7 × 10 = 440 m^{2}
Curved surface area of tank R = 2 × (22/7) × 2 × 28 = 352 m^{2}
Curved surface area of tank T = 2 × (22/7) × 3 × 21 = 396 m^{2}
Total curved surface area of tanks Q, R and T combined = (440 + 352 + 396) = 1188 m^{2}
Incorrect
E. None of these
Curved surface area of tank Q = 2 × (22/7) × 7 × 10 = 440 m^{2}
Curved surface area of tank R = 2 × (22/7) × 2 × 28 = 352 m^{2}
Curved surface area of tank T = 2 × (22/7) × 3 × 21 = 396 m^{2}
Total curved surface area of tanks Q, R and T combined = (440 + 352 + 396) = 1188 m^{2}
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