**Quadratic Equation Questions**

Hello Aspirants, As we all know that **Quadratic Equation Questions** is a important part of **quantitative aptitude** section for every competitive exams.Different kind of Quadratic Equation Questions asked in every competitative exam.So here, In this article we will provide Quadratic Equation Quiz.These **Quadratic Equation Questions** are important for Bank, SSC, SEBI, NABARD, RBI, LIC, and Other state exams. You can attempt these questions & boost your preparation for your examination.

In the Banking exams **Quadratic Equation Questions** asked in the Prelims as well as Mains exam.There are 5 Quadratic Equation Questions asked in the Prelims exam (Bank).You want to score more in the Quadratic Equation section then you should practice more and more Quadratic Equation.

**Quadratic Equation Questions Quiz -7**

**1. In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.**

**I. x ^{2} +14x -207 = 0**

**II. y**

^{2}-33y +266 = 0A. x < y

B. x > y

C. x ≤ y

D. x ≥ y

E. x = y or relationship cannot be established

**A. x < y**

From equation I:

x^{2} +14x -207 = (x + 23)(x -9)= 0

=> x = -23, 9

From equation II:

y^{2}-33y +266 = (y -19)(y -14) = 0

=> y = 19, 14

X = -23 | X = 9 | |

Y =19 | x < y | x < y |

Y = 14 | x < y | x < y |

So, x < y

**2.In the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x ^{2}-44x +483 = 0
II. 25y^{2} +15y -54 = 0**

A. x < y

B. x > y

C. x ≤ y

D. x ≥ y

E. x = y or relationship cannot be established

**B. x > y**

From equation I:

x^{2}-44x +483 = (x -21)(x -23)= 0

=> x = 21, 23

From equation II:

25y^{2} +15y -54 = (5y -6)(5y + 9) = 0

=> y = 6/5, -9/5

X = 21 | X = 23 | |

Y = 6/5 | x > y | x > y |

Y = -9/5 | x > y | x > y |

So, x > y

**3.In the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x ^{2}-31x +184 = 0
II. y^{2}-22y +96 = 0**

A. x < y

B. x > y

C. x ≤ y

D. x ≥ y

E. x = y or relationship cannot be established

**E. x = y or relationship cannot be established**

From equation I:

x^{2}-31x +184 = (x -8)(x -23)= 0

=> x = 8, 23

From equation II:

y^{2}-22y +96 = (y -6)(y -16) = 0

=> y = 6, 16

X = 8 | X = 23 | |

Y =6 | x > y | x > y |

Y = 16 | x < y | x > y |

So, relationship cannot be established between x and y

**4.In the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. 15x ^{2} +22x +8 = 0
II. y^{2} +y -462 = 0**

A. x < y

B. x > y

C. x ≤ y

D. x ≥ y

E. x = y or relationship cannot be established

**E. x = y or relationship cannot be established**

From equation I:

15x^{2} +22x +8 = (5x + 4)(3x + 2)= 0

=> x = -4/5, -2/3

From equation II:

y^{2} +y -462 = (y + 22)(y -21) = 0

=> y = -22, 21

X = -4/5 | X = -2/3 | |

Y =-22 | x > y | x > y |

Y = 21 | x < y | x < y |

So, relationship cannot be established between x and y

**5.In the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x ^{2}-5x -300 = 0
II. y^{2} +46y +528 = 0**

A. x < y

B. x > y

C. x ≤ y

D. x ≥ y

E. x = y or relationship cannot be established

**B. x > y**

From equation I:

x^{2}-5x -300 = (x + 15)(x -20)= 0

=> x = -15, 20

From equation II:

y^{2} +46y +528 = (y + 24)(y + 22) = 0

=> y = -24, -22

X = -15 | X = 20 | |

Y =-24 | x > y | x > y |

Y = -22 | x > y | x > y |

So, x > y

**6.In the following questions, two equations numbered I and II are given.You have to solve both the equations and choose the correct option.
187x ^{2} + 6x – 1 = 0
153y^{2}– 26y + 1 = 0**

A. If x ≤ y

B. If x ≥ y

C. If x < y

D. If x > y

E. If x = y or no specific relation cannot be established.

**A. If x ≤ y**

First equation is –

187x^{2} + 6x – 1 = 0

or, 187x^{2}– 11x + 17x – 1= 0

or, 11x (17x – 1) + 1 (17x – 1) = 0

or, (11x + 1) (17x – 1) = 0

x = – 1/11, 1/17

Second equation is –

153y^{2}– 26y + 1 = 0

or, 153y^{2}– 17y – 9y + 1 = 0

or, 17y (9y – 1) – 1 (9y – 1) = 0

or, (17y – 1) (9y – 1) = 0

y = 1/17, 1/9

y is always more than x or equal to x.

**7.In the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. 10x ^{2} +5x -5 = 0
II. y^{2}-16y +15 = 0**

A. x < y

B. x > y

C. x ≤ y

D. x ≥ y

E. x = y or relationship cannot be established

**A. x < y**

From equation I-

10x^{2} +5x -5 = (5x + 5)(2x -1)= 0

=> x = -5/5, 1/2

From equation II:

y^{2}-16y +15 = (y -1)(y -15) = 0

=> y = 1, 15

So, x < y

**8.In the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x = √484
II. 7y – 4x = 45**

A. x < y

B. x ≥ y

C. x > y

D. x ≤ y

E. x = y or the relationship between x and y cannot be determined

**C. x > y**

From I, x=22

From II, 7y – 88 = 45

=> 7y = 133

=> y = 19

Hence x > y

**9.In the following questions, two equations numbered I and II are given.You have to solve both the equations and choose the correct option.
I. 3.5x ^{2}– 28x + 42 = 0
II. 1.5y^{2} + 3y – 12 = 0**

A. x < y

B. x ≥ y

C. x > y

D. x ≤ y

E. x = y or the relationship between x and y cannot be determined

**B. x ≥ y**

From I, 3.5(x-2)(x-6) = 0

=> x = 2, 6

From II, 1.5(y-2)(y+4) = 0

=> y = 2, -4

Hence x ≥ y

**10.In the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I- y ^{6} = 729
II- x^{5} = 243**

A. x < y

B. x ≥ y

C. x > y

D. x ≤ y

E. x = y or the relationship between x and y cannot be determined

**B. x ≥ y**

From I, y = ±3

From II, x = 3

Hence x ≥ y