## Data Interpretation Questions For Bank

Hello Aspirants, As we all know that Data Interpretation is a vital part of quantitative aptitude section for every competitive exam. Data Interpretation is the process of making sense out of a collection of data that has been processed. This collection of data present in the form of charts. (Like – Tabular Chart, Bar Chart, Pie Chart, Line Chart, Missing Data Chart, Caselet Chart, and Radar Chart). So here, In this article, we will provide different charts with some questions. These Data Interpretation Questions are important for Bank, SSC, SEBI, NABARD, RBI, LIC, and Other state exams. You can attempt these questions & boost your preparation for your examination.

In the Banking exams, Data Interpretation Questions asked in the Prelims as well as Mains exam. There are 3-4 Data Interpretation asked in the mains exam (Bank). You want to score more in the Data Interpretation section then you should practice more and more Data Interpretations questions.

## Data Interpretation Questions Quiz-31

This “Data Interpretation Questions and Answers” is also important for other banking exams such as SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, IBPS RRB Officer, IBPS RRB Office Assistant, IBPS SO, SBI SO and other competitive exams.

Directions: (1-5) Answer the questions based on the information given below.

The given pie chart shows the percentage distribution of bankers of different banks in Uttar Pradesh circle. Total number of bankers in Uttar Pradesh circle is 13500.

% Distribution of Bankers 1.Find the average of number of bankers of Dena Bank, Canara Bank and Indian Bank.

A 2170
B 1825
C 2430
D 2865
E 3240

C.2430

Required average number of Bankers = ((15 + 18 + 21) ÷ 3)% of 13500

= 18% of 13500 = 2430

2.Find the difference between the number of bankers of Uco Bank and the number of bankers of Syndicate Bank.

A 550
B 675
C 725
D 640
E None of these

B. 675

Required difference = 17% of 13500 – 12% of 13500

= 5% of 13500 = 675

3.The total number of bankers of Dena bank and Canara bank taken together is what percentage more than the number of bankers of Indian bank?

A 61.11%
B 28.57%
C 44.44%
D 57.14%
E 72.72%

D. 57.14%

Number of bankers of Indian Bank = 0.21 × 13500 = 2835

Number of bankers of Canara Bank and Dena Bank together = 0.33 × 13500 = 4455

Therefore, required percentage = ((4455 – 2835)/2835) × 100 = 57.14%

4.If the ratio of the male bankers to female bankers of Indian bank and Dena Bank is 4:3 and 3:2 respectively, then find the difference between the number of female bankers of Indian bank and the number of male bankers of Dena bank.

A 0
B 12
C 15
D 20
E None of these

A. 0

Number of bankers of Indian Bank = 0.21 × 13500 = 2835

Number of bankers of Dena Bank = 0.15 × 13500 = 2025

Number of female bankers of Indian Bank = (3/7) × 2835 = 1215

Number of male bankers of Dena Bank = (3/5) × 2025 = 1215

Therefore, required difference = 1215 – 1215 = 0

5.If the ratio of male bankers to female bankers of Canara bank is 5:4, then number of female bankers of Canara Bank is what percentage of total number of bankers from Uco bank?

A 82.5%
B 66.67%
C 55.55%
D 45.45%
E 6.36%

B. 66.67%

Number of bankers of Canara Bank = 0.18 × 13500 = 2430

Number of bankers of Uco Bank = 0.12 × 13500 = 1620

Number of female bankers of Canara bank = (4/9) × 2430 = 1080

Therefore, required percentage = (1080/1620) × 100 = 66.67%

Directions: (6-10) Answer the questions based on the information given below.

The table below shows the population distribution of five towns of a district of Uttar Pradesh

 Town Population Ratio of male to female Percentage of literate male Percentage of illiterate female Nehtaur 15000 8:7 64% 54% Dhampur 35000 4:3 72% 64% Chandpur 20000 3:2 58% 54% Noorpur 18000 5:4 65% 60% Bijnor 42000 11:10 80% 56%

6.Find the difference between the total number of literate males from Nehtaur and Dhampur taken together and the total number of literate females from the same towns.

A 98700
B 10900
C 11400
D 72800
E 98200

B. 10900

Number of males from Nehtaur = (8/15) × 15000 = 8000

So, number of females from Nehtaur = 15000 – 8000 = 7000

Number of males from Dhampur = (4/7) × 35000 = 20000

So, number of females from Dhampur = 35000 – 20000 = 15000

Number of literate males from Nehtaur = 0.64 × 8000 = 5120

Number of literate females from Nehtaur = (100 – 54)% × 7000 = 3220

Number of literate males from Dhampur = 0.72 × 20000 = 14400

Number of literate females from Dhampur = (100 – 64)% × 15000 = 5400

Therefore, required difference = (5120 + 14400) – (3220 + 5400) = 10900

7.The number of literate females from Chandpur is approximately what percentage less than the number of literate males from Chandpur?

A 32%
B 28%
C 47%
D 58%
E 72%

C. 47%

Population of Chandpur = 20000

Number of males from Chandpur = (3/5) × 20000 = 12000

So, number of females from Chandpur = 20000 – 12000 = 8000

Number of literate female from Chandpur = (100 – 54)% × 8000 = 3680

Number of literate male from Chandpur = 0.58 × 12000 = 6960

Therefore, required percentage = ((6960 – 3680)/6960) × 100 ~ 47%

8.Find the average male population of each town.

A 14400
B 12800
C 11500
D 15250
E 16820

A. 14400

Number of males from Nehtaur = (8/15) × 15000 = 8000

Number of males from Dhampur = (4/7) × 35000 = 20000

Number of males from Chandpur = (3/5) × 20000 = 12000

Number of males from Noorpur = (5/9) × 18000 = 10000

Number of males from Bijnor = (11/21) × 42000 = 22000

Therefore, required average = (8000 + 20000 + 12000 + 10000 + 22000) ÷ 5 = 14400

9.Find the ratio of number of literate males from Bijnor to the number of literate females from the same town?

A 2:3
B 4:3
C 2:1
D 3:2
E 5:4

C. 2:1

Population of Bijnor = 42000

Number of males from Bijnor = (11/21) × 42000 = 22000

So, number of females from Bijnor = 42000 – 22000 = 20000

Number of literate female from Bijnor = (100 – 56)% × 20000 = 8800

Number of literate male from Bijnor = 0.80 × 22000 = 17600

Therefore, required ratio = 17600: 8800 = 2: 1

10.In the town Noorpur, if 35% of males and 40% of female didn’t cast their votes for the election of Nagar Panchayat, where two candidates contested for the election and the winning candidate won by 2486 votes, then find the number of votes received by runner up candidate.

A 3434
B 4407
C 3987
D 4274
E 4628

B.4407

Population of Noorpur = 18000

Number of males from Bijnor = (5/9) × 18000 = 10000

So, number of females from Bijnor = 18000 – 10000 = 8000

Votes casted by males of Bijnor = (100 – 35)% × 10000 = 6500

Votes casted by females of Bijnor = (100 – 40)% × 8000 = 4800

Let the number of votes received by runner up candidate be ‘x’.

So, according to question,

x + x + 2486 = 6500 + 4800

2x = 11300 – 2486

2x = 8814

x = 4407

So, the number of votes received by runner up candidate is 4407.

Note:

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