## FCI Practice Questions Set – Numerical Aptitude

FCI Phase I Practice Questions. FCI Quant Practice Questions. FCI Prelims Practice Set. FCI Numerical Aptitude Practice Questions. Welcome to the www.letsstudytogether.co online Numerical Aptitude section. If you are preparing for FCI Exam 2019  you will come across a section on Numerical Aptitude Section. Here we are providing you with English Language quiz on “FCI Practice Questions Numerical Aptitude for FCI Phase I Exam 2019”  for your daily practice.

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## FCI Practice Questions Numerical Aptitude | Set-2

1. What should come in place of question mark (?) in the following question?

100 × 10 – 100 + 3000 ÷ 100 = ?

A. 979
B. 920
C. 780
D. 930

Step-1- Parts of an equation enclosed in ‘Brackets’ must be solved first, and in the bracket, the BODMAS rule must be followed,

Step-2- Any mathematical ‘Of’ or ‘Exponent’ must be solved next,

Step-3-Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated,

Step-4-Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.

Given expression is,

100 × 10 – 100 + 3000 ÷ 100 = ?

⇒ (100 × 10) – 100 + (3000 ÷ 100) = ?

⇒ 1000 – 100 + 30 = ?

⇒ 900 + 30 = ?

⇒ ? = 930

2. What should come in place of question mark (?) in the following question?

(5.20)2 – 102.6 ÷ ? = 8.04

A. 5.4
B. 6.5
C. 8.2
D. 16

Follow BODMAS rule to solve this question, as per the order given below,

Step-1-Parts of an equation enclosed in ‘Brackets’ must be solved first,

Step-2-Any mathematical ‘Of’ or ‘Exponent’ must be solved next,

Step-3-Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated,

Step-4-Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.

Now, the given expression,

(5.20)2 – 102.6÷ ? = 8.04

⇒ 27.04 – 102.6/? = 8.04

⇒ 102.6/? = 27.04 – 8.04

⇒ ? = 102.6/19

⇒ ? = ​5.4

3. What should come in place of question mark (?) in the following question?

1.05% of 2500 + 2.5% of 440 =?

A. 37.75
B. 37.25
C. 35.75
D. 33.5

Given expression:

1.05% of 2500 + 2.5% of 440 =?

⇒ ? = 2500 × (1.05/100) + 440 × (2.5/100)

⇒ ? = 26.25 + 11

⇒ ? = 37.25

Hence, the required number in place of question mark is 37.25.

4. What should come in place of question mark (?) in the following question?

25114.25 – 7856.36 + 1425.28 =? – 4587
A. 14,257.36
B. 17,566.23
C. 23,270.17
D. 78,356.25

25114.25 – 7856.36 + 1425.28 =? – 4587

⇒ ? = 25114.25 – 7856.36 + 1425.28 + 4587

⇒ ? = 31126.53 – 7856.36

⇒ ? = 23,270.17

Hence, the required number in place of question mark is 23,270.17.

Directions (5-9) : Study the following data carefully and answer the questions given below.

The total number of schools and colleges in a state are 30000. The ratio of school and colleges in this state is 4:1. 30% of total numbers of schools are girl schools and 25% of the total numbers of schools are co-ed schools. The rest of the schools are boys schools. Out of total numbers of colleges 15% are girls colleges for general course. 5% of total numbers of colleges are degree engineering colleges and 2% of total numbers of colleges are diploma colleges. And 20% of total degree engineering colleges teach diploma courses also.

[Boys and girls both can be admitted in co-ed schools]

5. The numbers of schools where girls can be admitted is what percentage of the number of schools where boys can be admitted?

A. 87.50
B. 62.58
C. 78.57
D. 59.51

The total number of schools and colleges in a state are 30000.

The ratio of school and colleges in this state is 4:1.

So, the number of schools = 30000 × (4/5) = 24000

30% of total numbers of schools are girl schools.

So, the numbers of girls schools = 24000 × (30/100) = 7200

25% of the total numbers of schools are co-ed schools.

So, the numbers of co-ed schools = 24000 × (25/100) = 6000

And Boys and girls both can be admitted in co-ed schools.

∴ The numbers of schools where girls can be admitted = 7200 + 6000 = 13200

Rest of the schools is boys schools.

So, the numbers of boys schools = 24000 × [100 – (30 + 25)]% = 24000 × 45% = 24000 × (45/100) = 10800

Then the number of schools where boys can be admitted = 10800 + 6000 = 16800

∴ The required percentage = [(13200/16800) × 100]% = 78.57%.

6.  In how many colleges students can be admitted for diploma course?

A. 150
B. 200
C. 180
D. 120

The total number of schools and colleges in a state are 30000.

The ratio of school and colleges in this state is 4:1.

So, the number of colleges = 30000 × (1/5) = 6000

5% of total numbers of colleges are degree engineering colleges.

So, the numbers of degree engineering colleges = 6000 × (5/100) = 300

2% of total numbers of colleges are diploma colleges.

So, the numbers of diploma colleges offering diploma course = 6000 × (2/100) = 120

And 20% of total degree engineering colleges used to teach diploma courses also.

So, the numbers of degree engineering colleges offering diploma course = 300 × (20/100) = 60

∴ The total numbers of colleges where students can be admitted for diploma course = 120 + 60 = 180.

7. What is the ratio between numbers of degree engineering colleges and schools?

A. 1:80
B. 3:40
C. 1:50
D. 2:35

The total number of schools and colleges in a state are 30000.

The ratio of school and colleges in this state is 4:1.

So, the number of colleges = 30000 × (1/5) = 6000

5% of total numbers of colleges are degree engineering colleges.

So, the numbers of degree engineering colleges = 6000 × (5/100) = 300

The total number of schools and colleges in a state are 30000.

So, the number of schools = 30000 × (4/5) = 24000

∴ The ratio between numbers of degree engineering colleges and schools = 300:24000 = 1:80.

8. What is the number of girls colleges for general course in the state?

A. 975
B. 1025
C. 750
D. 900

The total number of schools and colleges in a state are 30000.

The ratio of school and colleges in this state is 4:1.

So, the number of colleges = 30000 × (1/5) = 6000

Out of total numbers of colleges 15% are girls colleges for general course.

∴ The number of girls colleges for general course in the state = 6000 × (15/100) = 900.

9. In how many schools can girls be admitted in the state?

A. 12330
B. 13200
C. 12500
D. 12540

The total number of schools and colleges in a state are 30000.

The ratio of school and colleges in this state is 4:1.

So, the number of schools = 30000 × (4/5) = 24000

30% of total numbers of schools are girl schools.

So, the numbers of girls schools = 24000 × (30/100) = 7200

25% of the total numbers of schools are co-ed schools.

So, the numbers of co-ed schools = 24000 × (25/100) = 6000

∵ Boys and girls both can be admitted in co-ed schools.

∴ The numbers of schools where girls can be admitted = 7200 + 6000 = 13200

10. In a company, 20% of the total employees are in the top management and 35% are in middle management. If 24 middle management employees get promoted to top management, there will be 22% of total employees in top management. How many employees are there in the company?

A. 880
B. 1000
C. 1200
D. 1440

Suppose there are T employees in company. If 24 middle management employees get promoted to top management, there will be 22% of total employees in top management instead of 20%.

⇒ 24 represents 2% employees of company.

⇒ 24 = T × (2/100)

⇒ T = 2400/2 = 1200

∴ There are 1200 employees in company. 