# Time and Work Problems For IBPS Exam 2017 : Set – 7 Time and Work Problems For IBPS Exam 2017. Welcome to the letsstudytogeter.co. In Quantitative AptitudeTime and work” is one of the important section in of the all Bank Exams. Here we provide you 10-15 set of Time and work questions with all possible type of questions in both English and Hindi language.

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Time and Work Quiz is important for exams such as IBPS PO, IBPS Clerk, IBPS RRB, SBI PO,RBI, NICL, SBI SO, LIC, IBPS Exams, SBI Exams and other competitive exams.

## Time and Work Problems For IBPS Exam 2017

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1. If 15 men or 24 women or 36 boys can do a piece of work in 12 days, working 8 h a day, how many men must be associated with 12 women and 6 boys to do another piece of work 2 ¼ times as great in 30 days working 6 h a day?

A. 4

B. 8

C. 6

D. 10

2. A, B and C can do a work in 8, 16, 24 days respectively. They all begin together. A continues to work till it is finished, C leaving off 2 days and B one day before its completion. In what time is work finished?

A. 5 days

B. 10 days

C. 15 days

D. 12 days

3. A and B can do a piece of work in 20 and 15 days respectively. They worked together for 6 days, after which B was replaced by C. If the work was finished in the next 4 days, then the number of days in which C alone could do the work will be

A. 60 days

B. 40 days

C. 35 days

D. 30 days

4. B can do a piece of work in 6 hours, B and C together can do it in 4 hours and A, B and C together in 2 2/3 hours. In how many hours can A and B together do the same piece of work?

A. 11 hour

B. 6 1/7 hour

C. 2  3/7  hour

D. 3  3/7 hour

5. P, Q, R are employed to do a work for Rs 5750. P and Q together finished 19/23 of work and Q and R together finished 8/23 of the work. Wage of Q, in rupees, is

A. 2850

B. 3750

C. 2750

D. 1000

6. A cistern has 3 pipes A, B and C. A and B can fill it in 3 and 4 hours respectively, and C can empty it in 1 hour. If the pipes are opened at 3 p.m., 4 p.m. and 5 p.m. respectively on the same day, the cistern will be empty at

A. 7 : 12 p.m.

B. 7 : 15 p.m.

C. 7 : 10 p.m.

D. 7 : 18 p.m.

7. If A works alone, he would take 4 days more to complete the job than if both A and B worked together. If B worked alone, he would take 16 days more to complete the job than if A and B work together. How many days would they take to complete the work if both of them worked together?

A. 10 days

B. 12 days

C. 6 days

D. 8 days

8. 250 men can finish a work in 20 days working 5 hours a day. To finish the work within 10 days working 10 hours a day, the minimum number of men required is

A. 310

B. 300

C. 250

D. 311

9. 2 men and 5 women can do a work in 12 days. 5 men and 2 women can do that work in 9 days. Only 3 women can finish the same work in

A. 36 days

B. 21 days

C. 30 days

D. 42 days.

10. Two pipes can separately fill a tank in 20 hours and 30 hours respectively. Both the pipes are opened to fill the tank but when tank is 1/3 full a leak develops in the tank through which 1/3 of the water supplied by both the pipes leak out. What is the total time taken to fill the tank?

A. 12 h

B. 16 h

C. 18 h

D. 15 h

## Time and Work Problems For IBPS Exam 2017

1. Option B.

15M = 23W  = 36B

SO, M­­­­­­1 * D1 * T1 *W1  = M2 * D2 * T2 * W2

15*12*8*9/4  =  ( 10+X)  *30*6  =  8

1. Option A.

According to the question-  X/ 8  +  (X-1)/16  + (X-2)/24 = 1

X = 5 Days.

1. Option B.

Work di-one by  A and B in 6 days = 6 × [ 1/20  +1/15] = 7/10

Remaining work  =  1- 7/10 = 3/10

If C is able to do  the work  in X days , then

4/20  +  4/X  = 3/10  = 40 days

1. Option D.

Work done by A in 1 hr =  work done by  A and C in 1 hr  – work done by B and C in 1 hr =

3/8  –  ¼   = 1/8

So, work done by A and C in 1 hr = 1/8  +1/6  = 7/24

Hence,  A and B  complete a piece of work in  24/7  days.

1. Option D.

Work done by  (P+Q+R) = 1 ………….(i)

Work done by  (P+Q) = 19/23 ………….(ii)

Work done by  (Q+R) = 8/23 ………….(iii)

FROM  (ii)  + (iii)  – (i)  =  Q = 19/23 +8/23  – 1 = 4/23

Work of Q = 4/23  ×5750  = 1000

1. Option A.

Part  of the cistern  filled  in 2hr by pipe A =  2/3

Part  of the cistern  filled  in 1hr by pipe B =  ¼

Total part filled up =  2/3  + ¼  = 11/12

When all pipe open  together = 1/3 +1/4 – 1  = – 5/12

So, time take to empty  11/12 part  = 11/12  × 12/5  =11/5 hr =  2hr 12 min

Req. time  5 + 2:12 = 7:12 pm

1. Option D.

According to the question = work by both  = √4×16  = √64 = 8 days

1. Option C.

According to the question =  250 *20*50 =            M2 * 10*10  = M2  = 250

1. Option A.

( 2M + 5 W ) ×  12 =  (5M +2W) × 9

2W = 1M

2M+5W = 9W =  9 × 12 = 3 ×D2 = 36 days.

1. Option B.

P1   20                    9

180

P2   30                    6

15

Time take to fill 1/3 rd  tank  = 180 /3× 5 =  4 Hr

After,  this actual  work  done by  ( P1 +P2)  =  (15) –  1/3 (15)

Time taken  for  fill  remaining  tank = 180 – 60 /10           =  12 hr

Total time Req.  for fill the tank =  4+12 = 16 Hr

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