Time and Work Practice Questions. Welcome to the letsstudytogeter.co. In Quantitative Aptitude “Time and work” is one of the important section in of the all Bank Exams. Here we provide you 10-15 set of Time and work questions with all possible type of questions in both English and Hindi language.
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Time and Work Quiz is important for exams such as IBPS PO, IBPS Clerk, IBPS RRB, SBI PO,RBI, NICL, SBI SO, LIC, IBPS Exams, SBI Exams and other competitive exams.
Time and Work Practice Questions
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1. 12 men can do a piece of work in 36 days. 18 women can do the same work in 60 days. 8 men and 20 women work together for 20 days. If the rest work has to be completed only by women in 4 days then how many women will complete it together?
A. 70
B. 28
C. 66
D. 40
2. In a fort there was sufficient food for 24 weeks for 200 soldiers. 80 more soldiers join the group at the end of one week and quantity of food served to each soldier was reduced from 900 gm to 750 gm. For how many days the rest food would last now?
A. 69
B. 138
C. 91
D. 276
3. A tank has three pipes. The first pipe can fill 1/2 part of the tank in 1 hour and the second pipe can fill 1/3 part in 1 hour. The third pipe is for making the tank empty. When all the three pipes are open, 7/12 th part of the tank is filled in 1 hour. How
A. 3 hours
B. 4 hours
C. 5 hours
D. 6 hours
4. 12 children take 16 days to complete a work which can be completed by 8 adults in 12 days. 16 adults started working and after 3 days 10 adults left and 4 children joined them. How many days will it take them to complete the remaining work?
A. 6
B. 8
C. 4
D. 3
5. Two pipes can fill a tank with water in 15 and 12 hours respectively and third pipe can empty it in 4hours. If the pipes be opened in order, at 8, 9 and 11 a.m. respectively, the tank will be emptied at-
A. 11 :40 am
B. 12 : 40 pm
C. 1 : 40 pm
D. 2 : 40 pm
6. A leak in the bottom of a cistern can empty the tank in 12 hours. An inlet pipe fills water at the rate of 5 liters a minute. When the tank is full the inlet pipe is also opened and due to the leak the tank is now empty in 15 hours. How many litres does the cistern hold?
A. 8260
B. 12000
C. 15000
D. 18000
7. A and B working together, can do a piece of work in 4 ½ hours. B and C working together can do it in 3 hours. C and A working together can do it in 2 ¼ hours. All of them begin the work at the same time. Find how much time they will take to finish the piece of work.
A. 3 hours
B. 2 hours
C. 2.5 hours
D. 1 hours
8. 2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days. In how many days can 2 men and 1 boy do the work ?
A. 8 days
B. 7 days
C. 12 ½ days
D. 2 days
9. P and Q together can do a job in 6 days. Q and R can finish the same job in 60/7 days. P started the work and worked for 3 days. Q and R continued for 6 days. Then the difference of days in which R and P can complete the job alone is ?
A. 10 days
B. 8 days
C. 12 days
D. 15 days.
10. A 10 hectare field is reaped by 2 men, 3 women and 4 children together in 10 days. If working capabilities of a man, a woman and a child are in the ratio 5 : 4 : 2, then a 16 hectare field will be reaped by 6 men, 4 women and 7 children in
A. 5 days
B. 6 days
C. 7 days
D. 8 days
Correct Answers
1. 12*36M=18*60W
1M= 5/2W
8M+20W=8* 5/2+ 20W =40W
40*20+ x*4=18*60
X=70W
Option (A)
2. 40*x = (500+x)*35
X=3500
(200*900)/280*750= x/23*7=> x= 138days
Options (B)
3. Emptied part by the third pipe in 1 hour
=(1/2+1/3)-1/12=1/4 Part
So, time taken by the third pipe to empty the tank= 4hrs
Option (B)
4. 12 Children*16days= 8adults *12days
192 children =96 adults.
Work done in 3 days by 16 adults= 16* (1/96)*3=1/2 Parts
So, (6adults+ 4 children’s) 1 days work= 6/96 +4/192 = 1/12
1/12 work is done by them in 1 day.
½ work will be done by them in= 12* ½= 6days
Option (A)
5. 
6.
Part of tank filled in one hour by inlet pipe = 1/12 – 1/15= 1/60Part
So, capacity of tank = (60*60*5)Liters.
18000 Liters.
Option (D)
7. 
8.
(2M+3B)*10= (3M+2B)*8
20M+30B = 24M+16B
4M=14B
M/B =7/2
- Total work = 200
- 2M+1B can do in = 12 ½ days.
Option (C)
9. Given, P+Q= 1/6
Q+R= 7/60
Work done by Q and R for 6 days= (7*6)/60= 42/60
Remaining work= 1- 42/60= 18/60= 3/10
No of days taken by P to complete the work= (10*3)*3 =10days
No of days taken by Q to complete the work=
1/(1/6-1/10)=15days
No of days taken by R to complete the work=
1/(7/60-1/15)= 20days
Required no of days= 20-10= 10days.
Option (A)
10. (2M+3W+4C)*10/10 = (6M+4W+7C)*D/16
M : W : C
5 : 4 : 2
(10+12+8)= (30+16+14)*D/16
= 30*16/16 =D
= D => 8 days
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