## Important Time and Work Questions

Important Time and Work Questions. Welcome to the www.letsstudytogether.co online Quant section. If you are preparing for SBI Clerk, SSC CPO, and Railway RRB Group D Exams, you will come across a section on Quantitative Aptitude. Here we are providing you Quant quiz on “Important Time and Work Questions” pattern for your daily practice.

“Time and Work Questions”  will help you learn concepts on important topics in Quant Section. This Quant subject quiz based on Important “Time and Work Questions and Answer” is also important for other banking exams such as IBPS PO, IBPS Clerk, SBI Clerk, IBPS RRB Officer, IBPS RRB Office Assistant, SSC CGL/CHSL/CPO, Railway RRB and other competitive exams.

## Important Time and Work Questions: Set-4

1.Gajendra, Jitendra and Satyendra can do a piece of work, working together, in 1 day. Gajendra is thrice efficient as Jitendra and Jitendra takes the twice the number of days as Satyendra takes to do it alone. What is the difference between the numbers of days taken by Gajendra and Satyendra?

1. 1
2. 2
3. 3
4. 4

C. 3 Days

Remember Time* 1/Efficiency

Gajendra                      Jitendra                      Satyendra

Efficiency      3                           :                          1                            :                         2

No. of days   2                :                          6                :                     3

Again,efficiency of Gajendra,Jitendra and Satyendra=100/1=100%

Efficiency of Gajendra=3/6*100=50%

Efficiency of Satyendra= 2/6*100=33.33%

Now,number of days taken by Gajendra= 100/50=2

Number of days taken by Satyendra=  100/33.33=3

2.Sonia and Saniya can complete a task in 30 days when working together, after Soniya and Saniya have been working together for 11 days, Saniya is called away and Soniya, all and himself completes the task in the next 28 days. Had Soniya been working alone, The number of days taken by him to complete the task would have been:

1. 33 3/19
2. 19 6/25
3. 44 4/19
4. None of these

C. 44 4/19 Days

Work done in 11 days =11/30

Rest work = 19/30

1 day’s work of Soniya =19/30/28= 19/30*28=19/840

Total number of days required to complete the whole work alone= 1/19/840=840/19=44 4/19 days

3.The ratio of efficiency  of Anita is to Chinmay is 5:3. The ratio of number of days taken by Bindu is to Chinmay is 2:3. Anita takes 6 days less than Chinmay, when Anita and Chinmay completes the work individuallu. Bindu and Chinmay started the work and left after 2 days. The Number of days taken by Anita to finish the remaining work is :

1. 4.5
2. 5
3. 6
4. 9 1/3

C. 6 Days

Anita                            Bindu               Chinmay

Efficiency        10                       :                         9                 :               6

No. of Days          9x                   :                         10x      :          15x

Now,      15x-9x=6

X=1

Number of days taken by Anita=9

Number of days taken by Bindu=10

Number of days taken by Chinmay=15

Work done by Bindu and Chinmay in initial 2 days= 2*1/6=1/3

Rest work=2/3

Number of days required by Anita to finish 2/3 work= 2/3÷1/9 =6days

4.  Arundhti can do a piece of work in 45 days, but Bahubali can do the same work in 5 days less than Arundhti, when working alone. Arundhti and Bahubali both started the work together but Bahubali left after some days and Arundhti finished the remaining work in 56 days with half of his efficiency but he did the work with Bahubali with his complete efficiency. For how many days they had worked together?

1. 6
2. 8
3. 9
4. 12

B. 8 Days

Arundhati                                            Bahubali

No. of Days                                                 45                                          40

Efficiency                                                  (1/45)=2.22%                    (1/40)=2.5%

Arundhati did the work in 56 days= 56×1/45×2=28/45

Rest work (17/45) was done by Arundhati and Bahubali= 17/45÷17/360= 8days

(Since Arundhati and Bahubali do the work in one day=1/45+1/40=17/360)

5.The number of days required by Aditi, Bipasha and Chandrika to work individually is 6, 12 and 18 respectively. They started a work doing it alternatively. If Aditi has started then followed by Bipasha and So on, how many days are needed to complete the whole work?

1. 8
2. 7.5
3. 8.5
4. 9.5

A. 8 Days

Efficiency of Bipasha=8.33%

Efficiency of Chandrika=12.5%

In 3 days Aditi,Bipasha,Chandrika completes 37.5% work

In 6 days Aditi,Bipasha,Chandrika completes 75% work

Rest work =25%

This 25% work will be completed by Aditi and Bipasha in next 2 Days

Thus total 6+2=8 days are needed.

6.When Taniya, Anjali and Nidhi are deployed for a task, Taniya and Anjali together do 70% of the work and Anjali and Nidhi together do 50% of the work. Who is the most efficient-?

1. Taniya
2. Anjali
3. Nidhi
4. Can’t be determined

A. Taniya

Taniya+ Anjali= 70%

Anjali  + Nidhi=  50%

[Taniya+ Anjali+Anjali+Nidhi-(Taniya+Anjali+Nidhi)=Anjali

70+50-100=20%

Anjali=20%, Taniya=50%, Nidhi= 30%

Taniya is most efficient

7. 16 men finished 1/3 work in 6 days. The number of additional men are required to complete the job in next 6 days.

1. 10
2. 8
3. 16
4. 32

C. 16

W×D= work

16×6=1/3W

Rest work= 2/3W

For double work in same time we need double women. So 16

More women are required

8. 30 workers can finish a work in 20 days. After how many days should 9 workers leave the job so that the work is completed in total 26 days:

1. 12
2. 10
3. 6
4. None of these

C. 6 Days

30×20=30*x+21*(26-x)

X=6

9.25 men can complete a job in 30 days. After how many days should the strength of work force be increased by 50 so that the work will be completed in 2/3 of the actual time:

1. 15 days
2. 10 days
3. 18 days
4. 5 days

A. 15 Days

25×30=25*x+75*(20-x)

X=15

10.6 men or 10 women can reap a field in 15 days, then the numbers of days that 12 men and 5 women will take to reap the same field is:

1. 5
2. 6
3. 8
4. 12

B. 6 Days

Work done by 6 Men= Work done by 10 women.

Work done by 1 man = work done by 10/6=5/3women

12men+5 women= 12*5/3+5=25women

W1×D1= W2×D2, W=women, D= days

10*15=25*D2

D2=6

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