 Quant Miscellaneous Questions for IBPS Clerk. Welcome to the www.letsstudytogether.co online Quant section. If you are preparing for IBPS PO/Clerk 2017 exam, you will come across a section on Quantitative Aptitude Section. Here we are providing you “Quant Miscellaneous Questions” for IBPS Clerk and Syndicate PO based on the latest pattern for your daily practice.

This “Quant Miscellaneous Questions” is also important for other banking exams such as IBPS PO, IBPS Clerk, SBI Clerk, IBPS  IBPS SO, SBI SO and other competitive exams

## Quant Miscellaneous Questions: Set-9

1.Arun and Salve can do a piece of work in 20 days and 25 days respectively. They began working together but Arun leaves the work after x number of days and Salve completes the remaining work in 7 days. If instead of Arun, Salve had left the work after x number of days, find the ratio of number of days it would Arun to finish the remaining work to the number of days in which Salve finished the remaining work.
a. 8/5
b. 4/9
c. 5/6
d. 4/5
e. 6/7

D. 4/5

Arun does 5% work per day and Slave does 4% work per day.
Together they do 9% work per day.
In seven days, Salve does 28% work.
Hence Arun and Salve must have completed 72% work when they worked together.
This implies that Arun left after working for 8 days.
If Salve had left the work after 8 days, Arun would have taken 28/5 days to complete the work.
Required ratio = 28/(5*7) = 4/5

2.The ratio of speeds of Aghosh and Soham is 4:5. Aghosh takes 30 minutes more than the time taken by Soham in reaching the destination. If their average speed is 36 km/h. Find the time taken by Aghosh to travel the same distance,if he increases his speed by 25%.
a. 2 hours
b. 2.5 hours
c. 1.5 hours
d. 1 hour
e. None of the above

A. 2 hours

Let their speeds be 4x and 5x.
Average speed = 9x/2.
9x/2 = 36.
x = 8.
Thus speed of Aghosh is 32 km per hour.
Let distance = y.
y/32 = y/40 + ½.
=> y = 80 km.
Speed of Aghosh if he increases his speed by 25% = 40 km/hour.
Time taken by Aghosh if he increases his speed by 25% = 80/40= 2 hours.

3.Nitesh and Dharma invest some amount of money in the ratio of 4:5 for the same period in a business. At the end of the year, they decide to donate 25% of the profit to a temple. Out the remaining, 80% was to be reinvested and the rest of the profit was divided in the ratio of their capital. If the difference in their shares is Rs.1800. Find the total profit.
a. Rs. 20000
b. Rs. 25000
c. Rs. 30000
d. Rs. 40000
e. None of these

E. None of these

Let the profit be Rs. 100.
Amount left after donation = 75.
Amount left after investment = 15.
Let the amount left after investment = Rs. x.
5x/9 -4x/9 = 1800.
=> x = 16200.
15% of the total profit = amount left after investment
Therefore total profit = (16200/15)*100 = Rs. 108000

4.A certain number of trucks were required to transport 80 tons of tea from a tea factory in Assam to Delhi. However, it was found that since each truck could take 0.8 tons of tea less, another 5 trucks were needed. If twice the number of trucks originally planned are used, how many tons of tea leaves can they carry to Delhi?
a. 64
b. 80
c. 72
d. 128
e. 144

D. 128

Let x number of trucks were used.
Then each truck’s capacity = 80/x tons.
But each truck carried (80/x – 0.8) tons.
New number of trucks = x+5.
(80/x – 0.8) * (x+5) = 80.
=> x = 20.
Each truck can carry 3.2 tons.
Hence if 40 trucks are used, they can transfer 128 tons of tea leaves from Assam to Delhi.

5.A man possessing Rs. 8000, lent a part of it at 10% simple interest and the remaining at 6% simple interest. His income after 4.5 years is Rs. 2880. Find the income generated by the sum lent at 10% at the end of 2 years.
a. Rs. 800
b. Rs. 900
c. Rs. 1200
d. Rs. 1350
e. Rs. 1400

A. Rs. 800

Annual interest income = 2880/4.5 = Rs. 640.
This implies an annual average rate of 8% per annum.
Thus 50% of Rs. 8000 is lent at 10%.
Income generated in 2 years by Rs. 4000 at 10% per annum = Rs. 800.

6. There are 7 people in an organization comprise of 2 boys and 5 men, each boy works at one-third the rate of each man, what is the ratio of time taken when all the 7 people are working together to the time taken when only 5 men are working together.
a. 17:15
b. 15:17
c. 6:5
d. 5:6
e. None of these

B. 15:17

Let a man takes x days so boy will take 3x days, work done by a man in one day is 1/x and by boy is 1/3x.
So work done by all in one day 5/x + 2/3x = 17/3x
Total number of days to finish work is 3x/17.
Number of days required by 5 men to finish the work is x/5 days.
Required ratio = 3x/17:x/5 = 15:17

7.Rahul can make 9 kites in 7 days. Karan can make 9 kites in 21 days. In how many days both together can make 36 kites?
a. 21 days
b. 25 days
c. 29 days
d. 15 days
e. 18 days

A. 21 days

Work done by Rahul in one day = 1/7
Work done by Karan in one day = 1/21
1/7 + 1/21 = 4/21
Number of days required by both of them together to make 9 kites = 21/4
Number of days required by both of them to make 36 kites = 21*4/4 = 21 days

8.If P/Q = 4/3, then find (P3+ 4Q2P)/(2Q3+ 3P2) = ?
a. 104/51
b. 104/17
c. 208/27
d. None of these
e. Cannot be determined

E. Cannot be determined

Let P and Q be 4k and 3k, where k is common factor of P & Q, substitute the value in given equation.
= [(4k)3+ 4*(3k)2*4k]/[2*(3k)3+3*(4k)2] = 104k/(27k+24)
As the value of k is not known, the value of required expression cannot be determined.

9.A student finds the average of 6 positive integers. Each integer contains two digits. By mistake, the boy interchanges the digits of one number say ba for ab. Due to this, the average becomes 6 less than the previous one. What is the difference of the two digits a and b?
a. 5
b. 3
c. 1
d. 9
e. 4

E. 4

Let the original number be ab i.e., (10a + b).
After interchanging the digits, the new number becomes ba i.e., (10b + a).
Therefore, the sum of the original 6 numbers will be 6 × 6 more than the sum of the 6 numbers with the digits interchanged.
i.e. 10a + b = 10b + a + 36
9a − 9b = 36
a – b = 4

10.There are 2 video CD’s A & B. The ratio of selling prices of these 2 CD’s is 7:8 and the ratio of their profit percentage is 4:1. Find the ratio of CP of Video CD’s A & B.
a. 1:1
b. 2:1
c. 4:1
d. Cannot be determined
e. None of these

D. Cannot be determined

Let the selling price be of the video CD be Rs 7a & 8a
Their profit percentages be 4y & y.
7a=CP1 (1+4y/100)
3a = CP2 (1+y/100) where CP1& CP2 are Cost Price of A & B.
From the above equations, it can be clearly seen that the ratio of CP1 & CP2 cannot be determined. 