Mission IBPS Clerk Mains 2017: Quadratic Equation Questions Day 5
Quadratic Equation Questions for IBPS Clerk Mains 2017. Welcome to the www.letsstudytogether.co online English section. If you are preparing for IBPS PO/Clerk 2017 and other competitive exams, you will come across a section of the Quant Section. Here we are providing you a Quant Quiz on Quadratic Equation for IBPS Clerk Mains Exam 2017″ based on the latest pattern for your daily practice.
LST Team created a Very special 30day IBPS Clerk Mains preparation Plan to crack IBPS Clerk Mains 2017, to help you study smarter and move closer to success. Here we provide you a Mission IBPS Clerk Mains 2017: Quadratic Equation Questions Day 5.
This “Quadratic Equation Quiz ″ is also important for other banking exams such as IBPS PO, IBPS Clerk, SBI Clerk, IBPS RRB Officer, IBPS RRB Office Assistant, IBPS SO, SBI SO and other competitive exams.
Quadratic Equation Questions for IBPS Clerk Mains Exam 2017: Set – 7
Mission IBPS Clerk Mains 2017: Quadratic Equation Quiz Day 5
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Mission IBPS Clerk Mains 2017: Quadratic Equation Quiz Day 5
Quantative Aptitude Section
No Of Question: 10
Test Time: 10 Mins
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Question 1 of 10
1. Question
Category: QuantIn the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x^{2} +14x 207 = 0
II. y^{2}33y +266 = 0Correct
From equation I:
x^{2} +14x 207 = (x + 23)(x 9)= 0
=> x = 23, 9
From equation II:
y^{2}33y +266 = (y 19)(y 14) = 0
=> y = 19, 14X = 23 X = 9 Y =19 x < y x < y Y = 14 x < y x < y So, x < y
Incorrect
From equation I:
x^{2} +14x 207 = (x + 23)(x 9)= 0
=> x = 23, 9
From equation II:
y^{2}33y +266 = (y 19)(y 14) = 0
=> y = 19, 14X = 23 X = 9 Y =19 x < y x < y Y = 14 x < y x < y So, x < y

Question 2 of 10
2. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x^{2}44x +483 = 0
II. 25y^{2} +15y 54 = 0Correct
From equation I:
x^{2}44x +483 = (x 21)(x 23)= 0
=> x = 21, 23
From equation II:
25y^{2} +15y 54 = (5y 6)(5y + 9) = 0
=> y = 6/5, 9/5X = 21 X = 23 Y = 6/5 x > y x > y Y = 9/5 x > y x > y So, x > y
Incorrect
From equation I:
x^{2}44x +483 = (x 21)(x 23)= 0
=> x = 21, 23
From equation II:
25y^{2} +15y 54 = (5y 6)(5y + 9) = 0
=> y = 6/5, 9/5X = 21 X = 23 Y = 6/5 x > y x > y Y = 9/5 x > y x > y So, x > y

Question 3 of 10
3. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x^{2}31x +184 = 0
II. y^{2}22y +96 = 0Correct
From equation I:
x^{2}31x +184 = (x 8)(x 23)= 0
=> x = 8, 23
From equation II:
y^{2}22y +96 = (y 6)(y 16) = 0
=> y = 6, 16X = 8 X = 23 Y =6 x > y x > y Y = 16 x < y x > y So, relationship cannot be established between x and y
Incorrect
From equation I:
x^{2}31x +184 = (x 8)(x 23)= 0
=> x = 8, 23
From equation II:
y^{2}22y +96 = (y 6)(y 16) = 0
=> y = 6, 16X = 8 X = 23 Y =6 x > y x > y Y = 16 x < y x > y So, relationship cannot be established between x and y

Question 4 of 10
4. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. 15x^{2} +22x +8 = 0
II. y^{2} +y 462 = 0Correct
From equation I:
15x^{2} +22x +8 = (5x + 4)(3x + 2)= 0
=> x = 4/5, 2/3
From equation II:
y^{2} +y 462 = (y + 22)(y 21) = 0
=> y = 22, 21X = 4/5 X = 2/3 Y =22 x > y x > y Y = 21 x < y x < y So, relationship cannot be established between x and y
Incorrect
From equation I:
15x^{2} +22x +8 = (5x + 4)(3x + 2)= 0
=> x = 4/5, 2/3
From equation II:
y^{2} +y 462 = (y + 22)(y 21) = 0
=> y = 22, 21X = 4/5 X = 2/3 Y =22 x > y x > y Y = 21 x < y x < y So, relationship cannot be established between x and y

Question 5 of 10
5. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x^{2}5x 300 = 0
II. y^{2} +46y +528 = 0Correct
From equation I:
x^{2}5x 300 = (x + 15)(x 20)= 0
=> x = 15, 20
From equation II:
y^{2} +46y +528 = (y + 24)(y + 22) = 0
=> y = 24, 22X = 15 X = 20 Y =24 x > y x > y Y = 22 x > y x > y So, x > y
Incorrect
From equation I:
x^{2}5x 300 = (x + 15)(x 20)= 0
=> x = 15, 20
From equation II:
y^{2} +46y +528 = (y + 24)(y + 22) = 0
=> y = 24, 22X = 15 X = 20 Y =24 x > y x > y Y = 22 x > y x > y So, x > y

Question 6 of 10
6. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
187x^{2} + 6x – 1 = 0
153y^{2}– 26y + 1 = 0Correct
First equation is –
187x^{2} + 6x – 1 = 0
or, 187x^{2}– 11x + 17x – 1= 0
or, 11x (17x – 1) + 1 (17x – 1) = 0
or, (11x + 1) (17x – 1) = 0
x = – 1/11, 1/17
Second equation is –
153y^{2}– 26y + 1 = 0
or, 153y^{2}– 17y – 9y + 1 = 0
or, 17y (9y – 1) – 1 (9y – 1) = 0
or, (17y – 1) (9y – 1) = 0
y = 1/17, 1/9
y is always more than x or equal to x.Incorrect
First equation is –
187x^{2} + 6x – 1 = 0
or, 187x^{2}– 11x + 17x – 1= 0
or, 11x (17x – 1) + 1 (17x – 1) = 0
or, (11x + 1) (17x – 1) = 0
x = – 1/11, 1/17
Second equation is –
153y^{2}– 26y + 1 = 0
or, 153y^{2}– 17y – 9y + 1 = 0
or, 17y (9y – 1) – 1 (9y – 1) = 0
or, (17y – 1) (9y – 1) = 0
y = 1/17, 1/9
y is always more than x or equal to x. 
Question 7 of 10
7. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. 10x^{2} +5x 5 = 0
II. y^{2}16y +15 = 0Correct
From equation I:
10x^{2} +5x 5 = (5x + 5)(2x 1)= 0
=> x = 5/5, 1/2
From equation II:
y^{2}16y +15 = (y 1)(y 15) = 0
=> y = 1, 15
So, x < yIncorrect
From equation I:
10x^{2} +5x 5 = (5x + 5)(2x 1)= 0
=> x = 5/5, 1/2
From equation II:
y^{2}16y +15 = (y 1)(y 15) = 0
=> y = 1, 15
So, x < y 
Question 8 of 10
8. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x = √484
II. 7y – 4x = 45Correct
From I, x=22
From II, 7y – 88 = 45
=> 7y = 133
=> y = 19
Hence x > yIncorrect
From I, x=22
From II, 7y – 88 = 45
=> 7y = 133
=> y = 19
Hence x > y 
Question 9 of 10
9. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. 3.5x^{2}– 28x + 42 = 0
II. 1.5y^{2} + 3y – 12 = 0Correct
From I, 3.5(x2)(x6) = 0
=> x = 2, 6
From II, 1.5(y2)(y+4) = 0
=> y = 2, 4
Hence x ≥ yIncorrect
From I, 3.5(x2)(x6) = 0
=> x = 2, 6
From II, 1.5(y2)(y+4) = 0
=> y = 2, 4
Hence x ≥ y 
Question 10 of 10
10. Question
Category: QuantIn the following questions, two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I y^{6} = 729
II x^{5} = 243Correct
From I, y = ±3
From II, x = 3
Hence x ≥ yIncorrect
From I, y = ±3
From II, x = 3
Hence x ≥ y
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