Important Quant Miscellaneous Questions for IBPS PO Prelims 2018
Important Quant Miscellaneous Questions for IBPS PO Prelims 2018. Welcome to the www.letsstudytogether.co online Quant section. If you are preparing for IBPS PO/Clerk exams 201718, you will come across a section on Quantitative Aptitude Section. Here we are providing you “Quant Miscellaneous Questions” for IBPS PO Prelims based on the latest pattern for your daily practice.
This “Quant Miscellaneous Questions for IBPS PO Prelims 2018” is also important for other banking exams such as SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, IBPS IBPS SO, SBI SO and other competitive exams
Important Quant Miscellaneous Questions for IBPS PO Prelims: Set24
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Question 1 of 10
1. Question
The speed of boat in still water is ‘x’ km/h and speed of stream is ‘y’ km/h. It can cover 75 km upstream in 5 hours. Now if the speed of the stream is increased by 40% then speed of the boat should be increased by 10% so as to cover the same distance upstream in the same time. Find the value of x.
Correct
C. 20 km/h
Speed of the boat in still water = x km/h and speed of stream = y km/h
Upstream speed = x – y = 75 ÷ 5
=> x – y = 15 …………………………… (i)
Now if speed of stream is increased by 40% and speed of boat is increased by 10%
1.10x – 1.40y = 75 ÷ 5
=> 1.10x – 1.40y = 15 ………………………… (ii)
Now solving (i) and (ii) we get x = 20 and y = 5
So, the value of ‘x’ = 20 km/h
Incorrect
C. 20 km/h
Speed of the boat in still water = x km/h and speed of stream = y km/h
Upstream speed = x – y = 75 ÷ 5
=> x – y = 15 …………………………… (i)
Now if speed of stream is increased by 40% and speed of boat is increased by 10%
1.10x – 1.40y = 75 ÷ 5
=> 1.10x – 1.40y = 15 ………………………… (ii)
Now solving (i) and (ii) we get x = 20 and y = 5
So, the value of ‘x’ = 20 km/h

Question 2 of 10
2. Question
Pooja and Neha can do a certain piece of work in 12 days when they work together. Neha can complete the work alone in ‘d’ days and she is 50% more efficient than Pooja. Find in how many days Pooja alone can do the same piece of work.
Correct
C. 30 days
Incorrect
C. 30 days

Question 3 of 10
3. Question
A basketball team of 5 players is to be formed from a group of 8 male and 5 female players. In how many ways the team can be formed so that at most 2 female players are selected.
Correct
D. 966 ways
The team can have two female players or only one female player or no female player.
So total number of ways = ^{5}C_{2} × ^{8}C_{3} + ^{5}C_{1} × ^{8}C_{4} + ^{8}C_{5} = 10 × 56 + 5 × 70 + 56 = 560 + 350 + 56 = 966 ways.
Incorrect
D. 966 ways
The team can have two female players or only one female player or no female player.
So total number of ways = ^{5}C_{2} × ^{8}C_{3} + ^{5}C_{1} × ^{8}C_{4} + ^{8}C_{5} = 10 × 56 + 5 × 70 + 56 = 560 + 350 + 56 = 966 ways.

Question 4 of 10
4. Question
A car can travel a distance of 450 km in 7.5 hours. He has to increase his average speed by ‘x’% so as to reduce the time by 1.5 hours. Find the value of x.
Correct
C. 25%
Incorrect
C. 25%

Question 5 of 10
5. Question
Sunil marked his bike 35% above cost price and sold it to Harish after a discount of D% on marked price. Find the value of D if in this transaction Sunil made a profit of 8%.
Correct
B. 20
Incorrect
B. 20

Question 6 of 10
6. Question
Pipes A and B can fill an empty tank in 45 minutes and 36 minutes, respectively. Pipe C can empty the tank in ‘x’ minutes at the rate 150 liters per minute. Find the capacity of tank if it takes 30 minutes to fill the tank when all the three pipes are opened at the same time.
Correct
A. 9000 liters
Incorrect
A. 9000 liters

Question 7 of 10
7. Question
Average of six consecutive odd numbers is twice the average of five consecutive even numbers. Find the difference between the largest odd number and smallest even number.
Correct
E. Data inadequate
Let the six consecutive odd numbers are 2x + 1, 2x + 3, 2x + 5, 2x + 7, 2x + 9, 2x + 11 and five consecutive even numbers are 2y, 2y + 2, 2y + 4, 2y + 6, 2y + 8.
So, average of odd numbers = (2x + 1 + 2x + 3 + 2x + 5 + 2x + 7 + 2x + 9 + 2x + 11) ÷ 6 = 2x + 6
Average of even numbers = (2y + 2y + 2 + 2y + 4 + 2y + 6 + 2y + 8) ÷ 5 = 2y + 4
According to question,
2x + 6 = 2 × (2y + 4)
=> x = 1 + 2y
Difference between largest odd number and smallest even number = (2x + 11) – 2y = 2(1 + 2y) + 11 – 2y = 2y + 13
Here we have neither the value of x nor of y, so data given is inadequate.
Incorrect
E. Data inadequate
Let the six consecutive odd numbers are 2x + 1, 2x + 3, 2x + 5, 2x + 7, 2x + 9, 2x + 11 and five consecutive even numbers are 2y, 2y + 2, 2y + 4, 2y + 6, 2y + 8.
So, average of odd numbers = (2x + 1 + 2x + 3 + 2x + 5 + 2x + 7 + 2x + 9 + 2x + 11) ÷ 6 = 2x + 6
Average of even numbers = (2y + 2y + 2 + 2y + 4 + 2y + 6 + 2y + 8) ÷ 5 = 2y + 4
According to question,
2x + 6 = 2 × (2y + 4)
=> x = 1 + 2y
Difference between largest odd number and smallest even number = (2x + 11) – 2y = 2(1 + 2y) + 11 – 2y = 2y + 13
Here we have neither the value of x nor of y, so data given is inadequate.

Question 8 of 10
8. Question
Present ages of Karan and Vivek are 7x and 9x, respectively and the present ages of Karan and Pankaj are in the ratio 4:3, respectively. If the present age of Pankaj is half of what the age of Vivek will be 6 years hence, then find the average age of Pankaj and Vivek at present.
Correct
C. 28 years 6 months
Incorrect
C. 28 years 6 months

Question 9 of 10
9. Question
Two cards are drawn from a well shuffled deck of playing cards. What is the probability that at least one card is a face card? (Only Jack, Queen and King are face cards)
Correct
A. 7/17
Incorrect
A. 7/17

Question 10 of 10
10. Question
The population of Delhi in 2014 is ‘x’. The population of Delhi increases by 15% every year with respect to its previous year and the population of Delhi in 2017 is 6,08,350. Find the value of ‘x’.
Correct
B. 4,00,000
Incorrect
B. 4,00,000
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