Important Quant Miscellaneous Questions for IBPS PO/Clerk Exams
Moderate Quant Miscellaneous Questions. Important Quant Miscellaneous Questions for IBPS PO/Clerk Prelims 2018. Welcome to the www.letsstudytogether.co online Quant section. If you are preparing for IBPS PO/Clerk exams 201718, you will come across a section on Quantitative Aptitude Section. Here we are providing you “Important Quant Miscellaneous Questions for IBPS PO/Clerk Prelims 2018“ based on the latest pattern for your daily practice.
This “Important Quant Miscellaneous Questions for IBPS PO/Clerk 2018 “ is also important for other banking exams such as SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, IBPS IBPS SO, SBI SO and other competitive exams
Important Quant Miscellaneous Questions for IBPS PO/Clerk Prelims  Set – 30
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
Help: Share this quiz to your Friends & FB Groups.
All the Best !!!
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Average score 

Your score 

Categories
 Not categorized 0%
Pos.  Name  Entered on  Points  Result 

Table is loading  
No data available  
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
P and Q can complete a work together in 18.75 days. If the product of the number of days taken by them to complete the work individually is 1500 days and the ratio of the number of days taken by P and Q was 5:3, then what was the number of days taken by P?
Correct
A. 50 days
Let the number of days taken by P and Q be ‘p’ and ‘q’ respectively. Then,
1/p + 1/q = 1/18.75
=>(p + q)/pq = 1/18.75
=>(p + q)/1500 = 1/18.75
=>p + q = 80
So, number of days taken by P to complete the work = (5/8) × 80 = 50 days
Incorrect
A. 50 days
Let the number of days taken by P and Q be ‘p’ and ‘q’ respectively. Then,
1/p + 1/q = 1/18.75
=>(p + q)/pq = 1/18.75
=>(p + q)/1500 = 1/18.75
=>p + q = 80
So, number of days taken by P to complete the work = (5/8) × 80 = 50 days

Question 2 of 10
2. Question
Superman and Spiderman won Rs. 600000 in a lottery and distributed it amongst them such that Superman’s share was Rs. ‘x’. Superman deposited his share at 6% simple interest for 3 years and Spiderman deposited his share at 4% simple interest for 2 years. If the sum of their accumulated amounts was Rs. 683000, then what was Superman’s share of lottery money?
Correct
C. Rs. 350000
According to the question,
[x × (1 + 0.06 × 3)] + [(600000 – x) × (1 + 0.04 × 2)] = 683000
[x × 1.18] + [(600000 – x) × 1.08] = 683000
1.18x + 648000 –1.08x = 683000
0.1x = 35000
x = Rs. 350000
Incorrect
C. Rs. 350000
According to the question,
[x × (1 + 0.06 × 3)] + [(600000 – x) × (1 + 0.04 × 2)] = 683000
[x × 1.18] + [(600000 – x) × 1.08] = 683000
1.18x + 648000 –1.08x = 683000
0.1x = 35000
x = Rs. 350000

Question 3 of 10
3. Question
Raj and Rohit started a business by investing Rs. ‘x + 15000’ and Rs. ‘x + 50000’ respectively. Raj withdrew Rs. 20000 at the end of the 3^{rd} month. Raj’s share of 1^{st} year’s profit of Rs. 16000 was Rs. 6000. Find ‘x’.
Correct
C. Rs. 75000
Profit sharing ratio between Raj and Rohit at the end of 1^{st} year
= [(x + 15000) × 3 + (x – 5000) × 9] : [(x + 50000) × 12]
= [12x] : [12x + 600000]
= (x) : (x + 50000)
According to the question,
(x/(x + x + 50000)) * 16000 = 6000
=>16000x = 12000x + 50000 * 6000
On solving x = Rs. 75000
Incorrect
C. Rs. 75000
Profit sharing ratio between Raj and Rohit at the end of 1^{st} year
= [(x + 15000) × 3 + (x – 5000) × 9] : [(x + 50000) × 12]
= [12x] : [12x + 600000]
= (x) : (x + 50000)
According to the question,
(x/(x + x + 50000)) * 16000 = 6000
=>16000x = 12000x + 50000 * 6000
On solving x = Rs. 75000

Question 4 of 10
4. Question
The total number of black cars and red cars in a showroom is 18. The number of red cars is 6 less than twice the number of black cars. If 3 cars are selected at random, what is the probability that at least one of them is Red?
Correct
B. 95/102
Let the number of black and red cars in the showroom be ‘x’ and ‘y’ respectively. So,
x + y = 18—(1)
y = 2x – 6—(2)
On solving (1) and (2), we get
x = 8 and y = 10
Required probability = P(atleast one of them is Red) = 1 – P(all of them are black)
= 1 – ((8/18) * (7/17) * (6/16))
= 1 – 7/102
= 95/102
Incorrect
B. 95/102
Let the number of black and red cars in the showroom be ‘x’ and ‘y’ respectively. So,
x + y = 18—(1)
y = 2x – 6—(2)
On solving (1) and (2), we get
x = 8 and y = 10
Required probability = P(atleast one of them is Red) = 1 – P(all of them are black)
= 1 – ((8/18) * (7/17) * (6/16))
= 1 – 7/102
= 95/102

Question 5 of 10
5. Question
3 cylinders of height ‘x’ cm and radius 42 cm are melted to form 4 cuboids of length, breadth, and height equal to 154 cm, 96 cm, and 9 cm respectively. What was the height of the cylinder?
Correct
D. 32 cm
According to the question,
The volume of 3 cylinders = Volume of 4 cuboids
3 × (22/7) × r^{2 }× h = 4 × l × b × h
3 × (22/7) × 42^{2 }× h = 4 × 154 × 96 × 9
16632 × h = 532224
So, h = 32 cm
Incorrect
D. 32 cm
According to the question,
The volume of 3 cylinders = Volume of 4 cuboids
3 × (22/7) × r^{2 }× h = 4 × l × b × h
3 × (22/7) × 42^{2 }× h = 4 × 154 × 96 × 9
16632 × h = 532224
So, h = 32 cm

Question 6 of 10
6. Question
A shopkeeper sold watch A costing Rs. 25000 at ‘x’% profit and watch B costing Rs. 24000 at ‘2x’% profit. If it is known that the sum of their selling prices was Rs. 63600, then what would have been the sum of their selling prices had each watch been sold at half of the original profit percentages?
Correct
B. Rs. 56300
According to the question,
25000 × (1 *+ x/100) + 24000 × (1 + 2x/100) = 63600
25000 + 250x + 24000 + 480x = 63600
730x = 14600
x = 20
Required sum = 25000 × (1 + 0.1) + 24000 × (1 + 0.2)
= 27500 + 28800 = Rs. 56300
Incorrect
B. Rs. 56300
According to the question,
25000 × (1 *+ x/100) + 24000 × (1 + 2x/100) = 63600
25000 + 250x + 24000 + 480x = 63600
730x = 14600
x = 20
Required sum = 25000 × (1 + 0.1) + 24000 × (1 + 0.2)
= 27500 + 28800 = Rs. 56300

Question 7 of 10
7. Question
Drum X and drum Y contain 300 litres and 500 litres of a mixture of milk and water in the ratio 3:7 and 11:9 respectively. ‘x%’ of liquid of drum X and drum Y is taken out and put into a bucket. If the total amount of water in the bucket is174 litres then find ‘x’.
Correct
A. 40
According to the question,
(x/100) × 300 × (7/10) + (x/100) × 500 × (9/20) = 174
2.1x + 2.25x = 174
4.35x = 174
x = 40
Incorrect
A. 40
According to the question,
(x/100) × 300 × (7/10) + (x/100) × 500 × (9/20) = 174
2.1x + 2.25x = 174
4.35x = 174
x = 40

Question 8 of 10
8. Question
A car is chasing a truck which is 60 km ahead of it. The speed of the car and the truck is ‘11x’ km/hr and ‘8x’ km/hr respectively. If the sum of the speed of the car and the truck is95 km/hr, then how long would it take the car to meet the truck?
Correct
B. 4 hours
According to the question,
11x + 8x = 95
19x = 95
x = 5
So, speed of the car and the truck is 55 km/hr and 40 km/hr respectively.
The time was taken by the car to meet the truck
= 60/(55 – 40)
= 60/15
= 4 hours
Incorrect
B. 4 hours
According to the question,
11x + 8x = 95
19x = 95
x = 5
So, speed of the car and the truck is 55 km/hr and 40 km/hr respectively.
The time was taken by the car to meet the truck
= 60/(55 – 40)
= 60/15
= 4 hours

Question 9 of 10
9. Question
M and N can complete a task in ‘8x’ days and ‘5x’ days respectively. They work together for 5 days and complete(13/40) part of the work. What is the difference between the number of days taken, when working alone, by M and N to complete the work?
Correct
D. 15 days
According to the question,
5 * (1/8x + 1/5x) = (13/40)
5 * (13x/40x^{2}) = 13/40
On solving, x = 5
So, the number of days taken by M and N are 40 and 25 respectively.
Required difference = 40 – 25 = 15 days
Incorrect
D. 15 days
According to the question,
5 * (1/8x + 1/5x) = (13/40)
5 * (13x/40x^{2}) = 13/40
On solving, x = 5
So, the number of days taken by M and N are 40 and 25 respectively.
Required difference = 40 – 25 = 15 days

Question 10 of 10
10. Question
The weights of A, B, C and D are 44 kgs, 40 kgs, 32 kgs and ‘x – 6’ kgs respectively. The average of weights of A and B was 2 kgs more than the average of weights of C and D. What is the average of weights of B, C and D?
Correct
B. 40 kgs
According to the question,
=>(44 + 40)/2 – (32 + (x – 6))/2 = 2
=>84/2 – (26 + x)/2 = 2
=>(84 – 26 – x) = 4
x = 54
So, D’s weight = 54 – 6 = 48 kgs
Required average = (40 + 32 + 48)/3 = 120/3 = 40 kgs
Incorrect
B. 40 kgs
According to the question,
=>(44 + 40)/2 – (32 + (x – 6))/2 = 2
=>84/2 – (26 + x)/2 = 2
=>(84 – 26 – x) = 4
x = 54
So, D’s weight = 54 – 6 = 48 kgs
Required average = (40 + 32 + 48)/3 = 120/3 = 40 kgs
Note:
 Click view Questions button to view Explanation
 Ask your doubt in comment section we’ ll clear your doubts in caring way.
 If you find any mistake, please tell us in the comment section and also mail us support@letsstudytogether.co
Crack IBPS PO Prelims 2018  Target 30 days Practice Sets of All Sections & Free PDF’s
High Level Quant & Data Interpretation PDF for Bank Exams
Books Name  Download Link 
Data Interpretation PDF for SBI PO Prelims 2018 – Based on SBI PO/Clerk Exams 2018  Click Here 
Quantitative Aptitude EBook for Banking, SSC and Insurance Exams  Click Here 
300 High Level Data Interpretation (DI) Questions & Answers PDF – Download Here  Click Here 
हाई लेवल डाटा इंटरप्रिटेशन प्रैक्टिस वर्कबुक (नवीनतम पैटर्न पर आधारित )  Click Here 
100 High Level Data Interpretation Questions & Answers PDF (English) Download Here  Click Here 
300 High Level Data Interpretation (DI) Questions & Answers PDF – Download Here
SBI PO/Clerk  RRB PO/Clerk  Railway Exams  SSC CGL 2018
S. No.  Exams  Direct Links 
1.  SBI PO/Clerk 2018  Click Here 
2.  IBPS RRB PO/Clerk 2018  Click Here 
3.  Railway RRB ALP & Group D 2018  Click Here 
4.  SSC CGL 2018  Click Here 