High Level Puzzles for IBPS PO/Clerk RRB OS/OA 2017 : Set – 47

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High Level Puzzles for IBPS PO/Clerk RRB OS/OA 2017. Welcome to Online Reasoning Section in letsstudytogether.co Here we are providing a set of Reasoning Ability Quiz for IBPS PO exams on Puzzle and seating arrangement.

High Level Puzzles for IBPS PO 2017

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Directions:(1-5) Read the following information and answer the questions.
There are 8 professors- P, Q, R, S, T, U, V and W sitting around a circular table (not necessarily in order) facing towards the center. They teach different programming languages- Java, C, PHP, SQL, Swift, Ruby, Python, and Perl (not necessarily in order) at the university. P sits opposite V. R sits exactly between T and W. The person sitting to the immediate left of P teaches Ruby. U teaches Python and sits exactly between V and P. U sits on the immediate right of T. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. R does not teach SQL.

1.Who teaches Ruby?

a. R
b. W
c. V
d. None of the above
e. Cannot be determined

Show Correct Answers

A. R

Let us give numbers to positions starting from P as 1, 2….8 in clockwise direction. Hence P is at 1 and V is at 5. The person sitting on the immediate left of P teaches Ruby, so he sits at position 2. U teaches Python and he is equidistant from V and P. So, U is at position 3 or 7.
Case 1:
U sits at position 7. U sits on the immediate right of T. So, T sits at position 8. R sits exactly between T and W. So,
Case 1.1 – R sits at position 2 and W sits at position 4. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, Q sits at position 6 and teaches Perl. V teaches C and P teaches Java. So, T teaches PHP and W teaches Swift. So, S who sits at position 3 teaches SQL.
Case 1.2 – R sits at position 3 and W sits at position 6. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. So, Q sits at position 4 and P teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift So no such case is possible So this case is rejected.

Case 2:
U sits at position 3. U sits on the immediate right of T. So, T sits at position 4. R sits exactly between T and W. So,
Case 2.1 – R sits at position 5 and W sits at position 8. So, Q sits at position 7 and teaches Perl. He sits exactly between the person who teaches C and the person who teaches Python. So, no such case is possible. So, this case is rejected.

Case 2.2 – R sits at position 7 and W sits at position 2. If Q sits at position 8 and teaches Perl. Then S sits at position 6. And V teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, no such case is possible. So, this case is rejected. If Q sits at position 6 and teaches Perl. V teaches Java. S teaches Swift. So, R
teaches SQL. But, R does not teach SQL. So, this case is rejected.

2. S teaches which programming language?
a. PHP
b. Java
c. Swift
d. SQL
e. Cannot be determined

Show Correct Answers

D. SQL

Let us give numbers to positions starting from P as 1, 2….8 in clockwise direction. Hence P is at 1 and V is at 5. The person sitting on the immediate left of P teaches Ruby, so he sits at position 2. U teaches Python and he is equidistant from V and P. So, U is at position 3 or 7.
Case 1:
U sits at position 7. U sits on the immediate right of T. So, T sits at position 8. R sits exactly between T and W. So,
Case 1.1 – R sits at position 2 and W sits at position 4. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, Q sits at position 6 and teaches Perl. V teaches C and P teaches Java. So, T teaches PHP and W teaches Swift. So, S who sits at position 3 teaches SQL.
Case 1.2 – R sits at position 3 and W sits at position 6. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. So, Q sits at position 4 and P teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift So no such case is possible So this case is rejected.

Case 2:
U sits at position 3. U sits on the immediate right of T. So, T sits at position 4. R sits exactly between T and W. So,
Case 2.1 – R sits at position 5 and W sits at position 8. So, Q sits at position 7 and teaches Perl. He sits exactly between the person who teaches C and the person who teaches Python. So, no such case is possible. So, this case is rejected.

Case 2.2 – R sits at position 7 and W sits at position 2. If Q sits at position 8 and teaches Perl. Then S sits at position 6. And V teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, no such case is possible. So, this case is rejected. If Q sits at position 6 and teaches Perl. V teaches Java. S teaches Swift. So, R
teaches SQL. But, R does not teach SQL. So, this case is rejected.

3.Who among the following in pairs sits opposite to each other?

a. Java- PHP language
b. T – SQL
c. U – S
d. Both (a) and (b)
e. Both (a) and (c)

Show Correct Answers

C. U – S

Let us give numbers to positions starting from P as 1, 2….8 in clockwise direction. Hence P is at 1 and V is at 5. The person sitting on the immediate left of P teaches Ruby, so he sits at position 2. U teaches Python and he is equidistant from V and P. So, U is at position 3 or 7.
Case 1:
U sits at position 7. U sits on the immediate right of T. So, T sits at position 8. R sits exactly between T and W. So,
Case 1.1 – R sits at position 2 and W sits at position 4. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, Q sits at position 6 and teaches Perl. V teaches C and P teaches Java. So, T teaches PHP and W teaches Swift. So, S who sits at position 3 teaches SQL.
Case 1.2 – R sits at position 3 and W sits at position 6. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. So, Q sits at position 4 and P teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift So no such case is possible So this case is rejected.

Case 2:
U sits at position 3. U sits on the immediate right of T. So, T sits at position 4. R sits exactly between T and W. So,
Case 2.1 – R sits at position 5 and W sits at position 8. So, Q sits at position 7 and teaches Perl. He sits exactly between the person who teaches C and the person who teaches Python. So, no such case is possible. So, this case is rejected.

Case 2.2 – R sits at position 7 and W sits at position 2. If Q sits at position 8 and teaches Perl. Then S sits at position 6. And V teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, no such case is possible. So, this case is rejected. If Q sits at position 6 and teaches Perl. V teaches Java. S teaches Swift. So, R
teaches SQL. But, R does not teach SQL. So, this case is rejected.

4. Who among the following in pairs sits next to each other?

a. Ruby – W
b. Perl – V
c. S – Java
d. T – R
e. None of the above

Show Correct Answers

B. Perl – V

Let us give numbers to positions starting from P as 1, 2….8 in clockwise direction. Hence P is at 1 and V is at 5. The person sitting on the immediate left of P teaches Ruby, so he sits at position 2. U teaches Python and he is equidistant from V and P. So, U is at position 3 or 7.
Case 1:
U sits at position 7. U sits on the immediate right of T. So, T sits at position 8. R sits exactly between T and W. So,
Case 1.1 – R sits at position 2 and W sits at position 4. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, Q sits at position 6 and teaches Perl. V teaches C and P teaches Java. So, T teaches PHP and W teaches Swift. So, S who sits at position 3 teaches SQL.
Case 1.2 – R sits at position 3 and W sits at position 6. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. So, Q sits at position 4 and P teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift So no such case is possible So this case is rejected.

Case 2:
U sits at position 3. U sits on the immediate right of T. So, T sits at position 4. R sits exactly between T and W. So,
Case 2.1 – R sits at position 5 and W sits at position 8. So, Q sits at position 7 and teaches Perl. He sits exactly between the person who teaches C and the person who teaches Python. So, no such case is possible. So, this case is rejected.

Case 2.2 – R sits at position 7 and W sits at position 2. If Q sits at position 8 and teaches Perl. Then S sits at position 6. And V teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, no such case is possible. So, this case is rejected. If Q sits at position 6 and teaches Perl. V teaches Java. S teaches Swift. So, R
teaches SQL. But, R does not teach SQL. So, this case is rejected.

5.Which of the following pairs are correctly matched?

a. R – Ruby
b. V- Python
c. W – Swift
d. Both a and b
e. Both a and c

Show Correct Answers

E. Both a and c

Let us give numbers to positions starting from P as 1, 2….8 in clockwise direction. Hence P is at 1 and V is at 5. The person sitting on the immediate left of P teaches Ruby, so he sits at position 2. U teaches Python and he is equidistant from V and P. So, U is at position 3 or 7.
Case 1:
U sits at position 7. U sits on the immediate right of T. So, T sits at position 8. R sits exactly between T and W. So,
Case 1.1 – R sits at position 2 and W sits at position 4. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, Q sits at position 6 and teaches Perl. V teaches C and P teaches Java. So, T teaches PHP and W teaches Swift. So, S who sits at position 3 teaches SQL.
Case 1.2 – R sits at position 3 and W sits at position 6. Q teaches Perl and he sits exactly between the person who teaches C and the person who teaches Python. So, Q sits at position 4 and P teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift So no such case is possible So this case is rejected.

Case 2:
U sits at position 3. U sits on the immediate right of T. So, T sits at position 4. R sits exactly between T and W. So,
Case 2.1 – R sits at position 5 and W sits at position 8. So, Q sits at position 7 and teaches Perl. He sits exactly between the person who teaches C and the person who teaches Python. So, no such case is possible. So, this case is rejected.

Case 2.2 – R sits at position 7 and W sits at position 2. If Q sits at position 8 and teaches Perl. Then S sits at position 6. And V teaches C. The person who teaches PHP sits to the immediate right of the person who teaches Java and opposite to the person who teaches Swift. So, no such case is possible. So, this case is rejected. If Q sits at position 6 and teaches Perl. V teaches Java. S teaches Swift. So, R
teaches SQL. But, R does not teach SQL. So, this case is rejected.

Directions (6-10) : Read the following information and answer the questions.
There are 7 couples living in a 7 storey building in which Ground floor is 1st floor, above that is 2nd floor, and so on, such that top most floor is 7th floor. The male members are- Sahil, Devesh, Anand, Taran, Tanay, Yash and Mohit. They are married to Swati, Ruchi, Puja, Bhavya, Aesha, Renu and Komal (not necessarily in order). Devesh lives on the 3rd floor with his wife Bhavya. Tanay lives on 7th floor. Puja lives on a floor exactly below that of Swati. The number of floors between the floors on which Ruchi and Bhavya live is same as the number of floors between the floors on which Swati and Aesha live. Sahil is married to Renu but they don’t live on a floor which is below that of Swati. There are 3 floors between the floors on which Sahil and Anand live. Taran does not live on a floor below that of Mohit and he does not live on a floor above that of Yash. Ruchi is not married to Yash or Mohit. Anand does not live on the 1st floor.

6. Who is married to Aesha?
a. Yash
b. Mohit
c. Anand
d. None of the above
e. Cannot be determined

Show Correct Answers

B. Mohit

Devesh lives on the 3rd floor with his wife Bhavya. Tanay lives on 7th floor. Puja lives exactly below Swati. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Sahil is married to Renu but they don’t live below Swati. Based on this data, Swati can be on 5th or 2nd floor.

Case 1: If Swati lives on 2nd floor.

There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya  as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. So, no such case is possible. So, this case is rejcted.

If Swati lives on 5th floor.
There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. This arrangement is possible only is Ruchi is on 7th floor, Swati is on 5th floor, Puja is on 4th floor and Aesha is on 1st floor. Hence, Aesha is married to Mohit.

7. Who is Komal’s husband?

a. Taran
b. Tanay
c. Anand
d. None of the above
e. Cannot be determined

Show Correct Answers

C. Anand

Devesh lives on the 3rd floor with his wife Bhavya. Tanay lives on 7th floor. Puja lives exactly below Swati. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Sahil is married to Renu but they don’t live below Swati. Based on this data, Swati can be on 5th or 2nd floor.

Case 1: If Swati lives on 2nd floor.

There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya  as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. So, no such case is possible. So, this case is rejcted.

If Swati lives on 5th floor.
There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. This arrangement is possible only is Ruchi is on 7th floor, Swati is on 5th floor, Puja is on 4th floor and Aesha is on 1st floor. Hence, Aesha is married to Mohit.

8. Yash lives on which floor?

a. 2nd
b. 4th
c. 5th
d. 6th
e. None of the above

Show Correct Answers

C. 5th

Devesh lives on the 3rd floor with his wife Bhavya. Tanay lives on 7th floor. Puja lives exactly below Swati. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Sahil is married to Renu but they don’t live below Swati. Based on this data, Swati can be on 5th or 2nd floor.

Case 1: If Swati lives on 2nd floor.

There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya  as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. So, no such case is possible. So, this case is rejcted.

If Swati lives on 5th floor.
There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. This arrangement is possible only is Ruchi is on 7th floor, Swati is on 5th floor, Puja is on 4th floor and Aesha is on 1st floor. Hence, Aesha is married to Mohit.

9.Which of the following pairs are correctly matched?

a. Tanay – Ruchi
b. 5th floor – Sahil
c. 4th floor – Puja
d. Both (a) and (b)
e. Both (a) and (c)

Show Correct Answers

E. Both (a) and (c)

Devesh lives on the 3rd floor with his wife Bhavya. Tanay lives on 7th floor. Puja lives exactly below Swati. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Sahil is married to Renu but they don’t live below Swati. Based on this data, Swati can be on 5th or 2nd floor.

Case 1: If Swati lives on 2nd floor.

There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya  as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. So, no such case is possible. So, this case is rejcted.

If Swati lives on 5th floor.
There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. This arrangement is possible only is Ruchi is on 7th floor, Swati is on 5th floor, Puja is on 4th floor and Aesha is on 1st floor. Hence, Aesha is married to Mohit.

10.Which of the following pairs are incorrectly matched?

a. Yash – Swati
b. 4th floor – Taran
c. 2nd floor – Anand
d. Mohit – Komal
e. None of the above

Show Correct Answers

D. Mohit – Komal

Devesh lives on the 3rd floor with his wife Bhavya. Tanay lives on 7th floor. Puja lives exactly below Swati. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Sahil is married to Renu but they don’t live below Swati. Based on this data, Swati can be on 5th or 2nd floor.

Case 1: If Swati lives on 2nd floor.

There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya  as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. So, no such case is possible. So, this case is rejcted.

If Swati lives on 5th floor.
There are 3 floors between Sahil and Anand. Anand does not live on the 1st floor. Hence Anand lives on 2nd floor and Sahil lives on 6th floor with Renu. Taran does not live below Mohit and he does not live above Yash. Hence Yash lives on 5th floor, Taran lives on 4th
floor and Mohit lives on 1st floor. There are same number of floors between Ruchi and Bhavya as well as Swati and Aesha. Ruchi is not married to Yash or Mohit. This arrangement is possible only is Ruchi is on 7th floor, Swati is on 5th floor, Puja is on 4th floor and Aesha is on 1st floor. Hence, Aesha is married to Mohit.


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