High Level Data Interpretation For SBI PO Prelims
High Level DI For SBI PO Prelims 2019. Data Interpretation Questions For SBI PO Prelims. Data Interpretation PDF For SBI PO Prelims. Welcome to the www.letsstudytogether.co online Quantitative Aptitude section. If you are preparing for upcoming SBI PO Prelims 2019, you will come across a section on Data Interpretation Section. Here we are providing you with “Data Interpretation Questions” For SBI PO Prelims 2019 based on the latest pattern of your daily practice.
This “High Level Data Interpretation For SBI PO Prelims 2019” is also important for other banking exams such as SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, IBPS RRB Officer, IBPS RRB Office Assistant, IBPS SO, SBI SO and other competitive exams.
Data Interpretation For SBI PO Prelims 2019  Set – 101
Directions:(15) Answer the questions based on the information given below.
The table given below provides information about the distribution of students in four different courses in five different colleges in the year 2010.
(Note: Colleges A, B, C, D and E offer only four courses i.e. B.Tech, MBA, BCA and MCA.)
The number of B.Tech students studying in college A is 75% more than the number of BCA students studying in the same college. The number of B.Tech students studying in college E and the number of MBA students studying in college E are in the ratio of 10: 9 respectively. The number of MBA students studying in college C is twice the number of BCA students studying in college C.
College

Number of students

Percentage distribution of students in different courses

B.Tech

MBA

BCA

MCA

A

7500

–

31%

–

25%

B

6800

25%

–

14%

35%

C

7200

27%

–

–

28%

D

6400

23%

34%

13%

–

E

8100

–

–

17%

26%

1.What is the total number of MCA students studying in all the five colleges combined in 2010?
A 10292
B 10297
C 10302
D 10307
E None of these
Show Correct Answers
Correct Answer – B.10297
Explanation:
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College

Number of students

Percentage distribution of students in different courses

B.Tech

MBA

BCA

MCA

A

7500

2100

0.31 × 7500 = 2325

1200

0.25 × 7500 = 1875

B

6800

0.25 × 6800 = 1700

1768

0.14 × 6800 = 952

0.35 × 6800 = 2380

C

7200

0.27 × 7200 = 1944

2160

1080

0.28 × 7200 = 2016

D

6400

0.23 × 6400 = 1472

0.34 × 6400 = 2176

0.13 × 6400 = 832

1920

E

8100

2430

2187

0.17 × 8100 = 1377

0.26 × 8100 = 2106

Total number of MCA students = 1875 + 2380 + 2016 + 1920 + 2106 = 10297
2.Number of MBA students studying in college B and D combined were approximately what percentage more than the number of BCA students studying in college A and E combined?
A 35%
B 42%
C 48%
D 53%
E 57%
Show Correct Answers
Correct Answer – D. 53%
Explanation:
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College

Number of students

Percentage distribution of students in different courses

B.Tech

MBA

BCA

MCA

A

7500

2100

0.31 × 7500 = 2325

1200

0.25 × 7500 = 1875

B

6800

0.25 × 6800 = 1700

1768

0.14 × 6800 = 952

0.35 × 6800 = 2380

C

7200

0.27 × 7200 = 1944

2160

1080

0.28 × 7200 = 2016

D

6400

0.23 × 6400 = 1472

0.34 × 6400 = 2176

0.13 × 6400 = 832

1920

E

8100

2430

2187

0.17 × 8100 = 1377

0.26 × 8100 = 2106

Number of MBA students studying in college B and D together = 1768 + 2176 = 3944
Number of BCA students studying in college A and E together = 1200 + 1377 = 2577
Desired percentage = (3944 – 2577)/2577 × 100 = 136700/2577 = 53.046% ~ 53%
3. Which college has the second lowest number of B.Tech students studying in it?
A A
B B
C C
D D
E E
Show Correct Answers
Correct Answer – B. B
Explanation:
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College

Number of students

Percentage distribution of students in different courses

B.Tech

MBA

BCA

MCA

A

7500

2100

0.31 × 7500 = 2325

1200

0.25 × 7500 = 1875

B

6800

0.25 × 6800 = 1700

1768

0.14 × 6800 = 952

0.35 × 6800 = 2380

C

7200

0.27 × 7200 = 1944

2160

1080

0.28 × 7200 = 2016

D

6400

0.23 × 6400 = 1472

0.34 × 6400 = 2176

0.13 × 6400 = 832

1920

E

8100

2430

2187

0.17 × 8100 = 1377

0.26 × 8100 = 2106

The number of B.Tech students studying in college B is second lowest.
4. The number of MBA students studying in college B in 2011 increased by 25% as compared to previous year. Find the number of MBA students studying in college B in 2011.
A 2210
B 2168
C 2110
D 2032
E None of these
Show Correct Answers
Correct Answer – A. 2210
Explanation:
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College

Number of students

Percentage distribution of students in different courses

B.Tech

MBA

BCA

MCA

A

7500

2100

0.31 × 7500 = 2325

1200

0.25 × 7500 = 1875

B

6800

0.25 × 6800 = 1700

1768

0.14 × 6800 = 952

0.35 × 6800 = 2380

C

7200

0.27 × 7200 = 1944

2160

1080

0.28 × 7200 = 2016

D

6400

0.23 × 6400 = 1472

0.34 × 6400 = 2176

0.13 × 6400 = 832

1920

E

8100

2430

2187

0.17 × 8100 = 1377

0.26 × 8100 = 2106

Number of MBA students studying in college B in 2011 = 1768 × 1.25 = 2210
5.What is the ratio of the number of B.Tech students studying in college A to the number of MCA students studying in college B?
A 5:7
B 9:10
C 15:17
D 29:34
E 21:23
Show Correct Answers
Correct Answer – C. 15:17
Explanation:
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College

Number of students

Percentage distribution of students in different courses

B.Tech

MBA

BCA

MCA

A

7500

2100

0.31 × 7500 = 2325

1200

0.25 × 7500 = 1875

B

6800

0.25 × 6800 = 1700

1768

0.14 × 6800 = 952

0.35 × 6800 = 2380

C

7200

0.27 × 7200 = 1944

2160

1080

0.28 × 7200 = 2016

D

6400

0.23 × 6400 = 1472

0.34 × 6400 = 2176

0.13 × 6400 = 832

1920

E

8100

2430

2187

0.17 × 8100 = 1377

0.26 × 8100 = 2106

Desired ratio = 2100 : 2380 = 15 : 17
Directions:(610) Answer the questions based on the information given below.
The pie chart given below provides information about the population of five different cities of Kangra in 2017. Population of Nagrota in 2017 was 60480.
Note: Total population of a city = Number of men + Number of women + Number of children
Male population = Number of men + Number of boys
Female population = Number of women + Number of girls
6.25% of the population in Dharaman are children out of which 11325 are boys. The number of women and number of men are in the ratio of 3:4 respectively. Find the difference in the male population and female population of Dharaman.
A 9050
B 9150
C 9250
D 9350
E 9450
Show Correct Answers
Correct Answer – B. 9150
Explanation:
Total population of all the five cities of Kangra = 60480 / 0.16 = 378000
Population of Dharaman = 0.25 × 378000 = 94500
Number of children in Dharaman = 0.25 × 94500 = 23625
Number of girls in Dharaman = 23625 – 11325 = 12300
Number of men and women combined in Dharaman = 94500 – 23625 = 70875
Number of women in Dharaman = 70875 × 3 / 7 = 30375
Number of men in Dharaman = 70875 × 4 / 7 = 40500
Male population of Dharaman = 40500 + 11325 = 51825
Female population of Dharaman = 30375 + 12300 = 42675
Required difference = 51825 – 42675 = 9150
7.In Jiya, 40% of the total population was literate. Population of Jiya was 30% less than the population of Chandpur. 65% of the population of village Chandpur is literate. Find the difference between the illiterate population of Jiya and Chandpur.
A 7260
B 7360
C 7460
D 7560
E None of these
Show Correct Answers
Correct Answer – D. 7560
Explanation:
Total population of all the five cities of Kangra = 60480 / 0.16 = 378000
Population of Jiya = 0.2 × 378000 = 75600
Literate population of Jiya = 0.40 × 75600 = 30240
Illiterate population of Jiya = 75600 – 30240 = 45360
Population of Chandpur = 75600 / 0.70 = 108000
Literate population of Chandpur = 0.65 × 108000 = 70200
Illiterate population of Chandpur = 108000 – 70200 = 37800
Required difference = 45360 – 37800 = 7560
8.35% of the population of Panchrukhi speaks English and 45% of the population of the Panchrukhi speaks Punjabi. 7212 people in Panchrukhi speak both Punjabi and English. Find the difference in the number of people who speak only English and the number of people who speak neither of the two languages.
A 776
B 796
C 816
D 836
E 856
Show Correct Answers
Correct Answer – C. 816
Explanation:
Total population of all the five cities of Kangra = 60480 / 0.16 = 378000
Population of Panchrukhi = 0.24 × 378000 = 90720
Population of Panchrukhi that speaks English = 0.35 × 90720 = 31752
Population of Panchrukhi that speaks Punjabi = 0.45 × 90720 = 40824
Population of Panchrukhi that speaks only English = 31752 – 7212 = 24540
Population of Panchrukhi that speak neither of the two languages = 90720 – 31752 – 40824 + 7212 = 25356
Required difference = 25356 – 24540 = 816
9.15% of the population of Nagrota and 10% of the population of Panchrukhi migrated to Baijnath due to which the population of Baijnath increased by 14%. Find the population of Baijnath before migration.
A 129600
B 108400
C 88200
D 64800
E None of these
Show Correct Answers
Correct Answer – A. 129600
Explanation:
Total population of all the five cities of Kangra = 60480/ 0.16 = 378000
Population of Panchrukhi = 0.24 × 378000 = 90720
Population of Panchrukhi migrated to Baijnath = 0.1 × 90720 = 9072
Population of Nagrota migrated to Baijnath = 0.15 × 60480 = 9072
Population of Baijnath before migration = (9072 + 9072)/0.14 = 129600
10.In 2017, the ratio of male population to female population of Alhilal was 4:5 respectively. In 2018, the male population of Alhilal increases by 32% as compared to previous year. Find the male population of Alhilal in 2018.
A 32348
B 32872
C 33264
D 33736
E None of these
Show Correct Answers
Correct Answer – C. 33264
Explanation:
Total population of all the five cities of Kangra = 60480 / 0.16 = 378000
Population of Alhilal in 2017 = 0.15 × 378000 = 56700
Male population of Alhilal in 2017 = 56700 / 9 × 4 = 25200
Male population of Alhilal in 2018 = 25200 × 1.32 = 33264
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