# High Level Data Interpretation For SBI PO Prelims 2019 Set – 101 High Level Data Interpretation For SBI PO Prelims 2019

## High Level Data Interpretation For SBI PO Prelims

High Level DI For SBI PO Prelims 2019. Data Interpretation Questions For SBI PO Prelims. Data Interpretation PDF For SBI PO Prelims. Welcome to the www.letsstudytogether.co online Quantitative Aptitude section. If you are preparing for upcoming SBI PO Prelims 2019, you will come across a section on Data Interpretation Section. Here we are providing you with  “Data Interpretation Questions” For SBI PO Prelims 2019 based on the latest pattern of your daily practice.

This “High Level Data Interpretation For SBI PO Prelims 2019 is also important for other banking exams such as SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, IBPS RRB Officer, IBPS RRB Office Assistant, IBPS SO, SBI SO and other competitive exams.

## Data Interpretation For SBI PO Prelims 2019 | Set – 101

Directions:(1-5) Answer the questions based on the information given below.

The table given below provides information about the distribution of students in four different courses in five different colleges in the year 2010.

(Note: Colleges A, B, C, D and E offer only four courses i.e. B.Tech, MBA, BCA and MCA.)

The number of B.Tech students studying in college A is 75% more than the number of BCA students studying in the same college. The number of B.Tech students studying in college E and the number of MBA students studying in college E are in the ratio of 10: 9 respectively. The number of MBA students studying in college C is twice the number of BCA students studying in college C.

 College Number of students Percentage distribution of students in different courses B.Tech MBA BCA MCA A 7500 – 31% – 25% B 6800 25% – 14% 35% C 7200 27% – – 28% D 6400 23% 34% 13% – E 8100 – – 17% 26%

1.What is the total number of MCA students studying in all the five colleges combined in 2010?

A 10292
B 10297
C 10302
D 10307
E  None of these

Correct Answer – B.10297

Explanation:

Let the number of BCA students studying in college A = x

So the number of B.Tech students studying in college A = 1.75x

So according to question: 1.75x + x = 7500 – 2325 – 1875

2.75x = 3300

So x = 1200

1.75x = 1.75 × 1200 = 2100

So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.

Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.

So according to question: 10y + 9y = 8100 – 1377 – 2106

19y = 4617, y = 243

9y = 9 × 243 = 2187

Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.

Let the number of BCA students studying in college C = z

So the number of MBA students studying in college C = 2z

So, according to question: z + 2z = 7200 – 1944 – 2016

3z = 3240, z = 1080

Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.

Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768

Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920

 College Number of students Percentage distribution of students in different courses B.Tech MBA BCA MCA A 7500 2100 0.31 × 7500 = 2325 1200 0.25 × 7500 = 1875 B 6800 0.25 × 6800 = 1700 1768 0.14 × 6800 = 952 0.35 × 6800 = 2380 C 7200 0.27 × 7200 = 1944 2160 1080 0.28 × 7200 = 2016 D 6400 0.23 × 6400 = 1472 0.34 × 6400 = 2176 0.13 × 6400 = 832 1920 E 8100 2430 2187 0.17 × 8100 = 1377 0.26 × 8100 = 2106

Total number of MCA students = 1875 + 2380 + 2016 + 1920 + 2106 = 10297

2.Number of MBA students studying in college B and D combined were approximately what percentage more than the number of BCA students studying in college A and E combined?

A 35%
B 42%
C 48%
D 53%
E 57%

Correct Answer – D. 53%

Explanation:

Let the number of BCA students studying in college A = x

So the number of B.Tech students studying in college A = 1.75x

So according to question: 1.75x + x = 7500 – 2325 – 1875

2.75x = 3300

So x = 1200

1.75x = 1.75 × 1200 = 2100

So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.

Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.

So according to question: 10y + 9y = 8100 – 1377 – 2106

19y = 4617, y = 243

9y = 9 × 243 = 2187

Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.

Let the number of BCA students studying in college C = z

So the number of MBA students studying in college C = 2z

So, according to question: z + 2z = 7200 – 1944 – 2016

3z = 3240, z = 1080

Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.

Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768

Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920

 College Number of students Percentage distribution of students in different courses B.Tech MBA BCA MCA A 7500 2100 0.31 × 7500 = 2325 1200 0.25 × 7500 = 1875 B 6800 0.25 × 6800 = 1700 1768 0.14 × 6800 = 952 0.35 × 6800 = 2380 C 7200 0.27 × 7200 = 1944 2160 1080 0.28 × 7200 = 2016 D 6400 0.23 × 6400 = 1472 0.34 × 6400 = 2176 0.13 × 6400 = 832 1920 E 8100 2430 2187 0.17 × 8100 = 1377 0.26 × 8100 = 2106

Number of MBA students studying in college B and D together = 1768 + 2176 = 3944

Number of BCA students studying in college A and E together = 1200 + 1377 = 2577

Desired percentage = (3944 – 2577)/2577 × 100 = 136700/2577 = 53.046% ~ 53%

3. Which college has the second lowest number of B.Tech students studying in it?

A A
B B
C C
D D
E E

Correct Answer – B. B

Explanation:

Let the number of BCA students studying in college A = x

So the number of B.Tech students studying in college A = 1.75x

So according to question: 1.75x + x = 7500 – 2325 – 1875

2.75x = 3300

So x = 1200

1.75x = 1.75 × 1200 = 2100

So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.

Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.

So according to question: 10y + 9y = 8100 – 1377 – 2106

19y = 4617, y = 243

9y = 9 × 243 = 2187

Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.

Let the number of BCA students studying in college C = z

So the number of MBA students studying in college C = 2z

So, according to question: z + 2z = 7200 – 1944 – 2016

3z = 3240, z = 1080

Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.

Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768

Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920

 College Number of students Percentage distribution of students in different courses B.Tech MBA BCA MCA A 7500 2100 0.31 × 7500 = 2325 1200 0.25 × 7500 = 1875 B 6800 0.25 × 6800 = 1700 1768 0.14 × 6800 = 952 0.35 × 6800 = 2380 C 7200 0.27 × 7200 = 1944 2160 1080 0.28 × 7200 = 2016 D 6400 0.23 × 6400 = 1472 0.34 × 6400 = 2176 0.13 × 6400 = 832 1920 E 8100 2430 2187 0.17 × 8100 = 1377 0.26 × 8100 = 2106

The number of B.Tech students studying in college B is second lowest.

4. The number of MBA students studying in college B in 2011 increased by 25% as compared to previous year. Find the number of MBA students studying in college B in 2011.

A 2210
B 2168
C 2110
D 2032
E None of these

Correct Answer – A. 2210

Explanation:

Let the number of BCA students studying in college A = x

So the number of B.Tech students studying in college A = 1.75x

So according to question: 1.75x + x = 7500 – 2325 – 1875

2.75x = 3300

So x = 1200

1.75x = 1.75 × 1200 = 2100

So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.

Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.

So according to question: 10y + 9y = 8100 – 1377 – 2106

19y = 4617, y = 243

9y = 9 × 243 = 2187

Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.

Let the number of BCA students studying in college C = z

So the number of MBA students studying in college C = 2z

So, according to question: z + 2z = 7200 – 1944 – 2016

3z = 3240, z = 1080

Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.

Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768

Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920

 College Number of students Percentage distribution of students in different courses B.Tech MBA BCA MCA A 7500 2100 0.31 × 7500 = 2325 1200 0.25 × 7500 = 1875 B 6800 0.25 × 6800 = 1700 1768 0.14 × 6800 = 952 0.35 × 6800 = 2380 C 7200 0.27 × 7200 = 1944 2160 1080 0.28 × 7200 = 2016 D 6400 0.23 × 6400 = 1472 0.34 × 6400 = 2176 0.13 × 6400 = 832 1920 E 8100 2430 2187 0.17 × 8100 = 1377 0.26 × 8100 = 2106

Number of MBA students studying in college B in 2011 = 1768 × 1.25 = 2210

5.What is the ratio of the number of B.Tech students studying in college A to the number of MCA students studying in college B?

A 5:7
B 9:10
C 15:17
D 29:34
E 21:23

Correct Answer – C. 15:17

Explanation:

Let the number of BCA students studying in college A = x

So the number of B.Tech students studying in college A = 1.75x

So according to question: 1.75x + x = 7500 – 2325 – 1875

2.75x = 3300

So x = 1200

1.75x = 1.75 × 1200 = 2100

So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.

Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.

So according to question: 10y + 9y = 8100 – 1377 – 2106

19y = 4617, y = 243

9y = 9 × 243 = 2187

Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.

Let the number of BCA students studying in college C = z

So the number of MBA students studying in college C = 2z

So, according to question: z + 2z = 7200 – 1944 – 2016

3z = 3240, z = 1080

Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.

Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768

Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920

 College Number of students Percentage distribution of students in different courses B.Tech MBA BCA MCA A 7500 2100 0.31 × 7500 = 2325 1200 0.25 × 7500 = 1875 B 6800 0.25 × 6800 = 1700 1768 0.14 × 6800 = 952 0.35 × 6800 = 2380 C 7200 0.27 × 7200 = 1944 2160 1080 0.28 × 7200 = 2016 D 6400 0.23 × 6400 = 1472 0.34 × 6400 = 2176 0.13 × 6400 = 832 1920 E 8100 2430 2187 0.17 × 8100 = 1377 0.26 × 8100 = 2106

Desired ratio = 2100 : 2380 = 15 : 17

Directions:(6-10) Answer the questions based on the information given below.

The pie chart given below provides information about the population of five different cities of Kangra in 2017. Population of Nagrota in 2017 was 60480.

Note: Total population of a city = Number of men + Number of women + Number of children

Male population = Number of men + Number of boys

Female population = Number of women + Number of girls 6.25% of the population in Dharaman are children out of which 11325 are boys. The number of women and number of men are in the ratio of 3:4 respectively. Find the difference in the male population and female population of Dharaman.

A  9050
B  9150
C  9250
D  9350
E  9450

Correct Answer – B. 9150

Explanation:

Total population of all the five cities of Kangra = 60480 / 0.16 = 378000

Population of Dharaman = 0.25 × 378000 = 94500

Number of children in Dharaman = 0.25 × 94500 = 23625

Number of girls in Dharaman = 23625 – 11325 = 12300

Number of men and women combined in Dharaman = 94500 – 23625 = 70875

Number of women in Dharaman = 70875 × 3 / 7 = 30375

Number of men in Dharaman = 70875 × 4 / 7 = 40500

Male population of Dharaman = 40500 + 11325 = 51825

Female population of Dharaman = 30375 + 12300 = 42675

Required difference = 51825 – 42675 = 9150

7.In Jiya, 40% of the total population was literate. Population of Jiya was 30% less than the population of Chandpur. 65% of the population of village Chandpur is literate. Find the difference between the illiterate population of Jiya and Chandpur.

A 7260
B 7360
C 7460
D 7560
E None of these

Correct Answer – D. 7560

Explanation:

Total population of all the five cities of Kangra = 60480 / 0.16 = 378000

Population of Jiya = 0.2 × 378000 = 75600

Literate population of Jiya = 0.40 × 75600 = 30240

Illiterate population of Jiya = 75600 – 30240 = 45360

Population of Chandpur = 75600 / 0.70 = 108000

Literate population of Chandpur = 0.65 × 108000 = 70200

Illiterate population of Chandpur = 108000 – 70200 = 37800

Required difference = 45360 – 37800 = 7560

8.35% of the population of Panchrukhi speaks English and 45% of the population of the Panchrukhi speaks Punjabi. 7212 people in Panchrukhi speak both Punjabi and English. Find the difference in the number of people who speak only English and the number of people who speak neither of the two languages.

A 776
B 796
C 816
D 836
E 856

Correct Answer – C. 816

Explanation:

Total population of all the five cities of Kangra = 60480 / 0.16 = 378000

Population of Panchrukhi = 0.24 × 378000 = 90720

Population of Panchrukhi that speaks English = 0.35 × 90720 = 31752

Population of Panchrukhi that speaks Punjabi = 0.45 × 90720 = 40824

Population of Panchrukhi that speaks only English = 31752 – 7212 = 24540

Population of Panchrukhi that speak neither of the two languages = 90720 – 31752 – 40824 + 7212 = 25356

Required difference = 25356 – 24540 = 816

9.15% of the population of Nagrota and 10% of the population of Panchrukhi migrated to Baijnath due to which the population of Baijnath increased by 14%. Find the population of Baijnath before migration.

A 129600
B 108400
C 88200
D 64800
E None of these

Correct Answer – A. 129600

Explanation:

Total population of all the five cities of Kangra = 60480/ 0.16 = 378000

Population of Panchrukhi = 0.24 × 378000 = 90720

Population of Panchrukhi migrated to Baijnath = 0.1 × 90720 = 9072

Population of Nagrota migrated to Baijnath = 0.15 × 60480 = 9072

Population of Baijnath before migration = (9072 + 9072)/0.14 = 129600

10.In 2017, the ratio of male population to female population of Alhilal was 4:5 respectively. In 2018, the male population of Alhilal increases by 32% as compared to previous year. Find the male population of Alhilal in 2018.

A 32348
B 32872
C 33264
D 33736
E None of these

Correct Answer  – C. 33264

Explanation:

Total population of all the five cities of Kangra = 60480 / 0.16 = 378000

Population of Alhilal in 2017 = 0.15 × 378000 = 56700

Male population of Alhilal in 2017 = 56700 / 9 × 4 = 25200

Male population of Alhilal in 2018 = 25200 × 1.32 = 33264

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