Hello Aspirants, As we all know that Data Interpretation is a vital part of quantitative aptitude section for every competitive exams. Data Interpretation is the process of making sense out of a collection of data that has been processed. This collection of data present in the form of charts.(Like – Tabular Chart, Bar Chart, Pie Chart, Line Chart, Missing Data Chart, Caselet Chart and Radar Chart).So here, In this article we will provide different charts with some questions.These Data Interpretation questions are important for Bank, SSC, SEBI, NABARD, RBI, LIC, and Other state exams. You can attempt these questions & boost your preparation for your examination.
In the Banking exams Data Interpretation questions asked in the Prelims as well as Mains exam.There are 3-4 Data Interpretation asked in the mains exam (Bank).You want to score more in the Data Interpretation section then you should practice more and more Data Interpretations questions.
This “Tabular and Pie Chart Data Interpretation Questions” is also important for other banking exams such as SBI PO, IBPS PO, IBPS Clerk, SBI Clerk, IBPS RRB Officer, IBPS RRB Office Assistant, IBPS SO, SBI SO and other competitive exams.
Tabular and Pie Chart Data Interpretation Quiz-8
Directions:(1-5) Answer the questions based on the information given below.
The table given below provides information about the distribution of students in four different courses in five different colleges in the year 2010.
(Note: Colleges A, B, C, D and E offer only four courses i.e. B.Tech, MBA, BCA and MCA.)
The number of B.Tech students studying in college A is 75% more than the number of BCA students studying in the same college. The number of B.Tech students studying in college E and the number of MBA students studying in college E are in the ratio of 10: 9 respectively. The number of MBA students studying in college C is twice the number of BCA students studying in college C.
College
Number of students
Percentage distribution of students in different courses
B.Tech
MBA
BCA
MCA
A
7500
–
31%
–
25%
B
6800
25%
–
14%
35%
C
7200
27%
–
–
28%
D
6400
23%
34%
13%
–
E
8100
–
–
17%
26%
1.What is the total number of MCA students studying in all the five colleges combined in 2010?
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College
Number of students
Percentage distribution of students in different courses
B.Tech
MBA
BCA
MCA
A
7500
2100
0.31 × 7500 = 2325
1200
0.25 × 7500 = 1875
B
6800
0.25 × 6800 = 1700
1768
0.14 × 6800 = 952
0.35 × 6800 = 2380
C
7200
0.27 × 7200 = 1944
2160
1080
0.28 × 7200 = 2016
D
6400
0.23 × 6400 = 1472
0.34 × 6400 = 2176
0.13 × 6400 = 832
1920
E
8100
2430
2187
0.17 × 8100 = 1377
0.26 × 8100 = 2106
Total number of MCA students = 1875 + 2380 + 2016 + 1920 + 2106 = 10297
2.Number of MBA students studying in college B and D combined were approximately what percentage more than the number of BCA students studying in college A and E combined?
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College
Number of students
Percentage distribution of students in different courses
B.Tech
MBA
BCA
MCA
A
7500
2100
0.31 × 7500 = 2325
1200
0.25 × 7500 = 1875
B
6800
0.25 × 6800 = 1700
1768
0.14 × 6800 = 952
0.35 × 6800 = 2380
C
7200
0.27 × 7200 = 1944
2160
1080
0.28 × 7200 = 2016
D
6400
0.23 × 6400 = 1472
0.34 × 6400 = 2176
0.13 × 6400 = 832
1920
E
8100
2430
2187
0.17 × 8100 = 1377
0.26 × 8100 = 2106
The number of B.Tech students studying in college B is second lowest.
4. The number of MBA students studying in college B in 2011 increased by 25% as compared to previous year. Find the number of MBA students studying in college B in 2011.
Let the number of BCA students studying in college A = x
So the number of B.Tech students studying in college A = 1.75x
So according to question: 1.75x + x = 7500 – 2325 – 1875
2.75x = 3300
So x = 1200
1.75x = 1.75 × 1200 = 2100
So the number of BCA students and the number of B.Tech students studying in college A are 1200 and 2100 respectively.
Let the number of B.Tech students and the number of MBA students studying in college E are 10y and 9y respectively.
So according to question: 10y + 9y = 8100 – 1377 – 2106
19y = 4617, y = 243
9y = 9 × 243 = 2187
Number of B.Tech students and the number of MBA students studying in college E are 2430 and 2187 respectively.
Let the number of BCA students studying in college C = z
So the number of MBA students studying in college C = 2z
So, according to question: z + 2z = 7200 – 1944 – 2016
3z = 3240, z = 1080
Number of BCA students and the number of MBA students studying in college C are 1080 and 2160 respectively.
Number of MBA students studying in college B = 6800 – 1700 – 952 – 2380 = 1768
Number of MCA students studying in college D = 6400 – 1472 – 2176 – 832 = 1920
College
Number of students
Percentage distribution of students in different courses
B.Tech
MBA
BCA
MCA
A
7500
2100
0.31 × 7500 = 2325
1200
0.25 × 7500 = 1875
B
6800
0.25 × 6800 = 1700
1768
0.14 × 6800 = 952
0.35 × 6800 = 2380
C
7200
0.27 × 7200 = 1944
2160
1080
0.28 × 7200 = 2016
D
6400
0.23 × 6400 = 1472
0.34 × 6400 = 2176
0.13 × 6400 = 832
1920
E
8100
2430
2187
0.17 × 8100 = 1377
0.26 × 8100 = 2106
Desired ratio = 2100 : 2380 = 15 : 17
Directions:(6-10) Answer the questions based on the information given below.
The pie chart given below provides information about the population of five different cities of Kangra in 2017. Population of Nagrota in 2017 was 60480.
Note: Total population of a city = Number of men + Number of women + Number of children
Male population = Number of men + Number of boys
Female population = Number of women + Number of girls
6.25% of the population in Dharaman are children out of which 11325 are boys. The number of women and number of men are in the ratio of 3:4 respectively. Find the difference in the male population and female population of Dharaman.
Total population of all the five cities of Kangra = 60480 / 0.16 = 378000
Population of Dharaman = 0.25 × 378000 = 94500
Number of children in Dharaman = 0.25 × 94500 = 23625
Number of girls in Dharaman = 23625 – 11325 = 12300
Number of men and women combined in Dharaman = 94500 – 23625 = 70875
Number of women in Dharaman = 70875 × 3 / 7 = 30375
Number of men in Dharaman = 70875 × 4 / 7 = 40500
Male population of Dharaman = 40500 + 11325 = 51825
Female population of Dharaman = 30375 + 12300 = 42675
Required difference = 51825 – 42675 = 9150
7.In Jiya, 40% of the total population was literate. Population of Jiya was 30% less than the population of Chandpur. 65% of the population of village Chandpur is literate. Find the difference between the illiterate population of Jiya and Chandpur.
Total population of all the five cities of Kangra = 60480 / 0.16 = 378000
Population of Jiya = 0.2 × 378000 = 75600
Literate population of Jiya = 0.40 × 75600 = 30240
Illiterate population of Jiya = 75600 – 30240 = 45360
Population of Chandpur = 75600 / 0.70 = 108000
Literate population of Chandpur = 0.65 × 108000 = 70200
Illiterate population of Chandpur = 108000 – 70200 = 37800
Required difference = 45360 – 37800 = 7560
8.35% of the population of Panchrukhi speaks English and 45% of the population of the Panchrukhi speaks Punjabi. 7212 people in Panchrukhi speak both Punjabi and English. Find the difference in the number of people who speak only English and the number of people who speak neither of the two languages.
Total population of all the five cities of Kangra = 60480 / 0.16 = 378000
Population of Panchrukhi = 0.24 × 378000 = 90720
Population of Panchrukhi that speaks English = 0.35 × 90720 = 31752
Population of Panchrukhi that speaks Punjabi = 0.45 × 90720 = 40824
Population of Panchrukhi that speaks only English = 31752 – 7212 = 24540
Population of Panchrukhi that speak neither of the two languages = 90720 – 31752 – 40824 + 7212 = 25356
Required difference = 25356 – 24540 = 816
9.15% of the population of Nagrota and 10% of the population of Panchrukhi migrated to Baijnath due to which the population of Baijnath increased by 14%. Find the population of Baijnath before migration.
Total population of all the five cities of Kangra = 60480/ 0.16 = 378000
Population of Panchrukhi = 0.24 × 378000 = 90720
Population of Panchrukhi migrated to Baijnath = 0.1 × 90720 = 9072
Population of Nagrota migrated to Baijnath = 0.15 × 60480 = 9072
Population of Baijnath before migration = (9072 + 9072)/0.14 = 129600
10.In 2017, the ratio of male population to female population of Alhilal was 4:5 respectively. In 2018, the male population of Alhilal increases by 32% as compared to previous year. Find the male population of Alhilal in 2018.
