B. 22.22%

Let, the number of Attempts taken by S = 3x
Number of Attempts taken by U = 4x
Therefore, number of Hits taken by S = 3x*(72/100) = 216x/100
And number of Hits taken by U = 4x*(66/100) = 264x/100
Therefore, required % = [{264x/100 – 216x/100}/(216x/100)]*100
= 22.22%

B. 70

Total Hits taken by T = Total Number of Matches * Average
= 28*27.5
= 770
According to the question,
Total Hits taken (Excluding last three matches) = 25*23 = 575
Therefore,
Total Hits in last three matches = 770 – 575 = 195
Average in last three matches = 195/3 = 65
It is given that the hits taken by T in 3rd and 2nd last matches in the competition are less than 64 and number of
hits taken in these 3 matches is different.
So, for minimum hits of T in the last match, it must score maximum in 3rd and 2nd last match.
Therefore,
Hits taken in 3rd last match = 62
Hits taken in 2nd last match = 63
Therefore,
Hits taken in the last match = 195 – 62 – 63 = 70

C. 18.5

According to the question,
A (Attempts taken) = 37 + H (Hits taken)
Let total number of attempts taken in the competition by P be x.
Therefore,
80 = {(x – 37)/x}*100
80x = 100x – 3700
20x = 3700
x = 185
Therefore,
Total number of Hits taken by P in the competition = 185 – 37 = 148
Therefore,
Required Average = 148/8 = 18.5

E. 1080

From the above table,
Total Number of Hits taken by Q in the competition = 20*40.5 = 810
Let total number of attempts taken by Q in the competition be x.
According to the question,
(x/2)*(70/100) + (x/2)*(80/100) = 810
7x + 8x = 16200
15x = 16200
x = 1080

C. 41

From the above table,
Total number of attempts taken by R in the competition = 800
Strike Rate = 82
Therefore,
Total number of Hits taken by R in the competition = 800*(82/100)
= 656
Also,
Average number of Hits taken by R = 16
Therefore,
Number of Matches played by R in the competition = 656/16= 41

B. 1700 million gallons

The total consumption of crude oil in the ten countries in 2010 = Total production + Total Import – Total Export =
(2300 + 1600 + 1900 + 2100 + 900 + 3100 + 5800 + 6000 + 5400 + 5200) + (300 + 400 + 500 + 400 + 1400 +1300 + 300 + 450 + 550 + 400) – (600 + 500 + 500 + 800 + 300 + 2100 + 4400 + 5100 + 4200 + 4800) = 34300
+ 6000 – 23300 = 17000 million gallons
Therefore, average consumption of crude oil in each of the ten countries in 2010 = 17000/10 = 1700 million gallons

D. 28.56% 

Total production of crude oil by country-3, country-4 and country-5 together in 2012 = 1900*1.25 +2100*1.22+900*1.24 = 6053 million gallons
Total export of crude oil by country-3, country-4 and country-5 together in 2012 = 500*1.25 + 800*1.2+300*1.25= 1960 million gallons
Total import of crude oil by country-3, country-4 and country-5 together in 2012 = 500*1.2 +400*1.15+1400*1.22 = 2768 million gallons
Total consumption of crude oil by country-3, country-4 and country-5 together in 2012 = 6053 -1960 + 2768 =6861 million gallons
Therefore, required percentage = 100*1960/6861 = 28.56 %

E. 45%

Production of crude oil in country-6 in 2012 = 3565million gallons
Export of crude oil in country-6 in 2012 = 2352 million gallons
Import of crude oil in country-6 in 2012 = 1495 million gallons
Consumption of crude oil in country-6 in 2012 = 3565 + 1495 – 2352 = 2708 million gallons
Production of crude oil in country-2in 2012 = 2000million gallons
Export of crude oil in country-2in 2012 = 620 million gallons
Import of crude oil in country-2in 2012 = 488 million gallons
Consumption of crude oil in country-6 in 2012 = 2000 + 620 – 488 = 1868 million gallons
Therefore, required percentage = 100*(2708-1868)/1868 = 44.97 % ≈ 45%

E. Country – 10

Country-10 witnessed the highest consumption.

C. Country – 5

Therefore, in 2012, crude oil import of Country – 5 forms the biggest portion of its total crude oil consumption.